M4maths Previous Puzzles

18 Apr 2011 Find the next

1,4,27,256, 3125, 46656

5, 31, 283, 3381, ?

OPtion

1) 46656
2) 46578
3) 49781
4) 33911
5) 56747
6) 44444
7) 67567
8) 12376
9) 49786
10) 29878

Solution

1^1, 2^2, 3^3, 4^4, 5^5, 6^6

1,4,27,256,3125,46656
1+4, 4+27, 27+256, 256+3125, 3125+46656
= 49781

Correct Option: 3 Best Solution (11)

dharmaveer   14 years AGO

1+4=5
4+27=31
27+256=283
256+3125=3381
3125+46656=49781

option 3

Like? Yes (7) | No (1)  

Balakumaran N.A   14 years AGO

From the given ques, 1+4,4+27,27+256,256+3125,3125+46656=Option 3...

Like? Yes (4) | No (1)  

A J V   14 years AGO

Just summation in second half of the series.

Like? Yes (3) | No (1)  

balaji   14 years AGO

(1^1), (2^2), (3^3), (4^4), (5^5), (6^6), (add 1st & 2nd term), (add 2nd & 3rd term), ... , (add 5th & 6th term).

Like? Yes (2) | No   

Gajendra Yadav   14 years AGO

4+1=5
4+27=31
27+256=283
256+3125=3381
3125+46656=49781......... this is the right Answer

Like? Yes (2) | No   

sandeep reddy m   14 years AGO

(n+1)^(n+1)+n^n

Like? Yes (2) | No   

atmakuri jagadish   14 years AGO

1(power 1),2(power 2),3(power3) .......so.on
second series is the sum of two numbers in the previous series

Like? Yes (2) | No (1)  

sanjeev   14 years AGO

the simple solution to this problem is as
to get the missing no of row 2...
we start like that..add first two no of first row we get the first element of second row for eg.
1+4 of first row=5 of second row
same way 4+27=31
27+256=283
3125+256=3381
now 46556+3125=49781..which is our missing term...

Like? Yes (2) | No (1)  

Seema   14 years AGO

1+4=5
4+27=31
similarly
3125+46656=49781

Like? Yes (1) | No   

raghunath reddy   14 years AGO

1+4=5
4+27=31
27+256=283
256+3125=3381
3125+46656=49781

Like? Yes (1) | No   

sivakumar   14 years AGO

1+4=5; 4+27=31....3125+46656=49781;

Like? Yes (1) | No