Three natural numbers x, y and z are such that x + y^2 + z^3 = 15 How many set of values of x, y an

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03 May 2012 natural numbers

Three natural numbers x, y and z are such that x + y^2 + z^3 = 15
How many set of values of x, y and z are possible.

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) none of these

Solution

For z only 1 and 2 are possible values so
13, 1, 1
10, 2, 1
5, 3, 1
6, 1, 2
3, 2, 2

Correct Option: 5 Best Solution (7)

Rakesh Kumar Kohli   12 years AGO

Different set of values of x,y,z are given below (it is not mentioned that all x,y,z are different so equal values are also taken) :

(x,y,z) = (5,3,1),(10,2,1),(6,1,2),(3,2,2), (13,1,1)

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manudixit   12 years AGO

ans:: 5 sets
soln: as eq x+y^2+z^3=15
possible max value for z= (1(1^3),8(2^3))
possible max value for y= (1(1^2),4(2^2),9(3^2))
now with combination of y and z we can values for
set1 :(x=13,y=1,z=1)
set2 :(x=10,y=2,z=1)
set3 :(x=5,y=3,z=1)
set4 :(x=3,y=2,z=2)
set5 :(x=6,y=1,z=2)

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Shiv Kumar   12 years AGO

Possible Combinations are:

1) z =1, y=1, x=13
2) z =1, y=2, x=10
3) z =1, y=3, x=5
4) z =2, y=1, x=6
5) z =2, y=2, x=3

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vignesh waran A   12 years AGO

(x,y,z) Possible values are

(3,2,2) , (6,1,2), (5,3,1), (10,2,1) & (13,1,1).

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saravana kumar   12 years AGO

(13,1,1) (6,1,2) (10,2,1) (3,2,2) (5,3,1)
these are the possibilities, considering natural numbers from 1,2,3,...

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sridhar reddy   12 years AGO

x+y^2+z^3=1
the values of (x,y,z) are
(13,1,1),(10,4,1),(5,9,1),(6,1,8),(3,4,8)

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kusuma   12 years AGO

6,1,2
13,1,1
3,2,2
10,2,1
5,3,1

Like? Yes (1) | No (1)