Dr.Dipin Singh   12 years AGO

areas of a square of side 10 cm. and rectangle of sides 11 cm. and 9 cm are 100 sq cm and 99 sq cms.

sum of areas = 199 sq cm
diff of areas = 100-99= 1 sq cms

Sum of the sum and positive difference of areas of a square of side 10 cm. and rectangle of sides 11 cm. and 9 cm. will be 199+1= 200 sq cms.

Like? Yes (5) | No (1)  

Ajay Kashyap   12 years AGO

area of square = 100
area of Rectangle = 99
difference = 1
sum = 199
sum of sum and difference is = 200

Like? Yes (3) | No   

hemant k kaushik   12 years AGO

area of square=100
area of rectangle=99
sum=199
diff=1
sum of sum & diff=199+1=200

Like? Yes (2) | No   

GIRISH TYAGI   12 years AGO

area of square is = 100
area of rectangle is = 99
so according to question the answer is
=(100+99)+(100-99)=200
option (4) is correct

Like? Yes (2) | No   

Pargat Pal Singh   12 years AGO

sum = 100+99=199
positive difference = 100-99=1
sum of sum and diff of areas= 199+1=200

Like? Yes (2) | No (1)  

phani   12 years AGO

area of square a*a=10*10=100
area of rectangular=11*9=99
difference=1
sum=199
sum of both=199+1=200

Like? Yes (2) | No (1)  

Karthick Babu   12 years AGO

areas of square 100
areas of rect 99
diff =1
sum=199
sum+diff=200

Like? Yes (2) | No (1)  

phani   12 years AGO

area of square a*a=10*10=100
area of rectangular=11*9=99
difference=1
sum=199
sum of both=199+1=200

Like? Yes (1) | No   

shwetha P.T.   12 years AGO

its sum=sum+diff
sum=199+1
=200

Like? Yes (1) | No   

DANISH EQUBAL   12 years AGO

area of square=100
area of rect=99
so a/q-
100+99=199
100-99=1
so
199+1=200

Like? Yes (1) | No   

Swetha   12 years AGO

square area=10*10=100
rectangle area=11*9=99
sum of areas=100+99=199
difference of areas=100-99=1
sum of the sum and diefference of areas=199+1=200

Like? Yes (1) | No   

asim   12 years AGO

arra of square = 100 sq.cm
area of rect = 99 sq. cm
sum of area = 199 sq. cm
positive difference of area = 1 sq. cm
thus required sum = 199+1 = 200 sq cm

Like? Yes (1) | No   

B.Senthil Kumar   12 years AGO

Area of Square=10*10=100
Area of Rectangle=11*9=99
Sum=100+99=199
Difference=100-99=1
so 199+1=200

Like? Yes (1) | No   

aanchal sharma   12 years AGO

area of square=100,area of rectangle=99.
sum=(100+99)+(100-99)=200

Like? Yes (1) | No   

Arpit Agarwal   12 years AGO

area of square=100 cm2
area of rectangle=99cm2
ans= (100+99)+(100-99)

Like? Yes (1) | No   

Niraj   12 years AGO

Sum of areas = 100+99 = 199
Positive Difference of areas = 100-99 = 1
So Sum= 199+1 = 200

Like? Yes (1) | No   

prem kumar.s   12 years AGO

area of square =10^2=100
area of rectangle=11*9=99
difference of square and rectangle=1
sum of square and rectangle=199
so
sum of this =199+1=200

Like? Yes (1) | No   

S. Singh   12 years AGO

Sum of the sum and positive difference of areas of a square of side 10 cm. and rectangle of sides 11 cm. and 9 cm. = (100+99)+(100-99)= 199+1=200

Like? Yes (1) | No   

sugumar   12 years AGO

area of square=a^2 so area=100
area of rectangle=2(l+b) so area=2*20=40
sum of area=100+40 and difference of area=60
so sum of the sum=140+60=200

Like? Yes (1) | No   

richa   12 years AGO

area of square 10*10=100 & Area of reactangle-11*9=99,so, sum of area =199,
difference of area=1,
sum of sum and difference=200

Like? Yes (1) | No   

vignesh waran A   12 years AGO

area of squre = 100
area of rect = 99

diff = 1 +
sum = 199
--------------------
tot sum = 200
--------------------

Like? Yes (1) | No   

Denis   12 years AGO

Area of square = 10^(2)= 100
Area of rectangle = 11*9= 99
So sum of area = 199
Difference of area = 1
So sum of the last 2 values = 200

Like? Yes (1) | No   

sathyasagar   12 years AGO

sum= 10*10 + 11*9 = 199
difference= 10*10 - 11*9 = 1

199 + 1 = 200

Like? Yes (1) | No   

Gaurav   12 years AGO

area of square: 10*10 = 100
area of rectangle: 11*9= 99

positive diffrence= 100-99=1
sum = 100+99= 199

and their sum = 199+1 = 200

Like? Yes (1) | No   

Nithin Reddy Bathula   12 years AGO

sum of the sum and positive difference means

(100+99)+(100-99)=199+1=200

Like? Yes (1) | No   

kewal   12 years AGO

Sum of the sum and positive difference of areas of a square of side 10 cm. ( i.e 100 sq cms)and rectangle of sides 11 cm. and 9 cm.(i.e 99 sq cms) will be 200 sq cms.

Like? Yes (1) | No (1)  

Balakrishnan M   12 years AGO

Area of the Square = 100 sqr.cm
Area of the Rectangle = 99 sqr.cm
Sum of the both Areas = 199 sqr.cm
& Positive difference of the the Areas = 1 sqr.cm
==> Sum of the sum and positive difference of areas = 199+1 = 200 sqr.cm

Like? Yes (1) | No (1)  

anand   12 years AGO

square=10 * 10=100
Rectangle=11 * 9=99

sum=199
difference=1
final sum=200

Like? Yes (1) | No (1)  

Jailani   12 years AGO

area of square=a^2=10*10=100
area of rect =l*b=11*9=99
sum=100+99=199
diffe=100-99=1
total sum=199+1=200

Like? Yes (1) | No (1)  

Devendra Marghade   12 years AGO

Sum of the areas=[(10*10)+(11*9)]+[(10*10)-(11*9)]
=(100+99)+(100-99)=199+1
=200

Like? Yes (1) | No (2)