Suggestion Board Post your query related to m4maths
If you have any query and suggestion you can submit it here.
Name
Email (will not be published)
Comment
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
13 years ago
Dear sandeep,
question is
x + y^2 = 17
17 > y + x^2 > 14
here x and y are real numbers greater than 1
then y-x will be
Check a case in which x=3.31 and y=3.7
so x + y^2 = 17
and y + x^2 = 3.7 + (3.31)^2 = 14.6561
similarly many other cases
Dear SANDEEP, DIPIN and INDER
in this question x and y are real numbers not integers, so 17 > y + x^2 > 14 is possible for any real set.
and INDER you wrote in your comment that
In today's puzzle,
one condition is
17 > y + x^2 > 14
it means
17>14
which is not correct.
Why 17 is not greater than 14. As far as we know 17 is greater than 14
Please check the admin's answer once again
Thanks