~Sandeep~ 13 years AGO

Dear admin,
I am confused wid todays puzzle solution of 3rd jan 2012, can you please tell us values of x and y greater than 1 which satisfies all conditions .
Sandeep.

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~Sandeep~ 13 years AGO

Hi Inder,
Agree with you...but there are 10 different options to choose and at least one of them I could see is still valid.

Cannot tell you the exact answer though :)

Sandeep.

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Inder 13 years AGO

In today's puzzle,

one condition is

17 > y + x^2 > 14

it means
17>14
which is not correct.

Pls check.

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hareesh 13 years AGO

pls to send me the shortcut formulas and methods of the aptitude test.

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mps gupta 13 years AGO

For today's puzzle I thought the speed will go till 100km/hr in 8th hour, but that doesn't seem to happen as per the given solution.

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~Sandeep~ 13 years AGO

For today's puzzle I thought the speed will go till 100km/hr in 8th hour, but that doesn't seem to happen as per the given solution.

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DIPIN 13 years AGO

missing series
4 4 6 12 30 --


missing series
4 4 6 12 30 90

4*1=4
4*1.5=6
6*2=12
12*2.5= 30
30*3=90

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Pargat Pal Singh 13 years AGO

congratulations, Dipin.

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yelender 13 years AGO

@ yelender goud :: pls to send me the shortcut formulas and methods of the aptitude test.

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DIPIN 13 years AGO

Dear Sandeep and Saranjit,

Thanks a lot.

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~Sandeep~ 13 years AGO

Congratulations Dipin!!!

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Saranjit Singh 13 years AGO

Congratulations, Dipin for solving 100 placement puzzles and winning a prize.

All the best.

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~Sandeep~ 13 years AGO

No Problem...you are welcome TIJO :)

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Tijo Jose 13 years AGO

@Sandeep: Yeah! How silly of me to think "all intersection points to be distinct" :) Thanks Buddy!!

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~Sandeep~ 13 years AGO

@TIJO: Not sure what did meant by "Can anyone tell me, how to draw 5 lines, which intersect only at a single point?"
Please refer following image where 5 lines are intersecting at one point:
http://tinyurl.com/8xf9mqx

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Tijo Jose 13 years AGO

The solution to 15-Dec-2011 says minimum number of intersection points of 5 lines is 1. Please help me understand this.

According to me, If no two pair of lines are parallel, then every pair must intersect at some point. Hence the minimum (and obviously,, the maximum also) number of intersection points has to be 10.

Please tell me where i am wrong in my calculation. Can anyone tell me, how to draw 5 lines, which intersect only at a single point? Thanks :)

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selva krishnan 13 years AGO

The puzzle is
there are three type of boxes,gold,silver,lead,
gold says, " ring is not in silver,
Silver says ," silver is not here,
lead says," ring is here"
Questions are where is the ring?
which one is say true and false?

i want answer 4 this

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sairam 13 years AGO

The puzzle is
there are three type of boxes,gold,silver,lead,
gold says, " ring is not in silver,
Silver says ," silver is not here,
lead says," ring is here"
Questions are where is the ring?
which one is say true and false?


i want answer 4 this

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Karthick Babu 13 years AGO

For (6-12-20110 puzzle) velocities in m/s are 18*5/18 = 5 m/s and 90*5/18 = 25 m/s
and 2 km = 2000 m
so acceleration = 30*20/2*2000 = 0.15
=(m/s*m/s)/m
=m/s^2
Answer should be in m/s^2 unit
but opt 10 is none of these. opt 10 only create big confusion on this Question.

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Koushik Paul 13 years AGO

@Balakumaran: Its ok........you are welcome...

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Koushik Paul 13 years AGO

Sorry friends the unit will be m/sec^2....

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Koushik Paul 13 years AGO

I am agree with Dipin about todays (6-12-11) puzzle's option. The unit of accelaration is m^2/sec no m/s....What a silly mistake...

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Balakumaran N.A 13 years AGO

@DIPIN: I agree with You for Today's (6.12.11) Puzzle.

Acceleration = m / sec^2 always...

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Balakumaran N.A 13 years AGO

@KALIDAS (2011-12-01):Agree with KALIDAS;
Pls check qn.
x^4 when divided by 6, will provide (here x is prime number) ????

Qn is not clear.
What is actually desired ???

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Balakumaran N.A 13 years AGO

@KOUSHIK PAUL: I got it, Thanks a lot for your Solution on 24.11.11;

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~Sandeep~ 13 years AGO

Agree with Dipin.
"None of these" option is very confusing in such cases.

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DIPIN 13 years AGO

In today's puzzle
The formula for finding the acceleration of the car is
a = (product of sum and difference of velocities)/2(total distance)
In a journey of 2 km, initial and final velocities of the car are 18 km/hr and 90 km/hr respectively. Calculate the acceleration.


I think Units of the accelration in given options are m/s due to printing mistake otherwise it should be m/sec ^2.

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Koushik Paul 13 years AGO

Agree with KALIDAS

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Kalidas 13 years AGO

Pls check today's qn.
x^4 when divided by 6, will provide (here x is prime number) ????

Qn is not clear.
What is actually desired ???

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DIPIN 13 years AGO

Dear Admin,

Thanks a lot for taking necessary action.

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suryambika 13 years AGO

admin sir...
i m for ABES ENGINEERING COLLEGE GHAZIBAD...
but the name of college is not in the list of colleges when filling the profile information.. please update is college name in list of uptu colleges.. otherwise give a column where students can give their college name if that is not in list..

please update my college name as ABES ENGG COLLEGE

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~Sandeep~ 13 years AGO

Would someone from m4maths look into last 7 comments and post a clarification /correction?

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Mihir 13 years AGO

Admin sir,

Pls check sol of this puzzle and give correct solution .

6 boys and 7 girls are available for a counselling. In how many ways, we can arrange them in a row, if middlest one is a boy and girls are sat on both the corners.

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Jason 13 years AGO

I think that observation made by Dipin and sandeep is correct.

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~Sandeep~ 13 years AGO

@Admin Sir are you listening.... feeling bad to see my last day point as -2 :)
---------------------------------------------
Last Day Points -2
My Answer 6

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Mihir 13 years AGO

I think Dipin and Sandeep are right.

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DIPIN 13 years AGO

Thanks Sandeep for confirming that.

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~Sandeep~ 13 years AGO

Agree with Dipin. Please check the solution

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DIPIN 13 years AGO

Dear Admin,
Pls check sol for thursday puzzle

6 boys and 7 girls are available for a counselling. In how many ways, we can arrange them in a row, if middlest one is a boy and girls are sat on both the corners.


Answer accepted is 126*10! which may not be correct.
As there are 7 girls . They can be selectede in group of two in 21 ways.
In each group, these 2 girls can be placed on two corners in 2 ways.

6 ways for boy at centre
2* 21 ways for girls at corners
10! ways for remaining 10 children at other 10 places.
So total arrangements are 2* 6*21*10!= 252*10!...option 6

Pls correct me if I am wrong.

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Koushik Paul 13 years AGO

@BALAKUMARAN : At first u should read yhe puzzle carefully...When the American time is 16.30 then Indian time should be (16.30+5.30)=22.00. Here we should add the time not subtruct. Because in the problem it is clearly mentioned that the time diff. between India & America is +5.30 not -5.30. If in the problem there mentioned that the time diff. between America & India is +5.30 then we should subtract the time, one thing also why u can mix up between time format?...got it...Is it helpfull to you plz reply...

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Koushik Paul 13 years AGO

@TAMALIKA : The ans should be D) Rs. 9000

Because A do the business for 12 months and B do the business for 7 months.
Let B contribute Rs. x.
so, 3500*12 : 7x = 2 : 3
=> x =(3500*12*3)/(7*2) = 9000....
If it is helpfull to you plz reply...
I have an query, don't mind..where r u from ?...

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Balakumaran N.A 13 years AGO

Dear Admin,
For Yesterday (21.11.11) puzzle, The following solution also possible. Plane starts at 11.00 (india time) and Lands at 16.30 (america time)...then, It Lands at 16.30-5.30=11.00(according to india time)...

So, time difference between starting and landing must be (11.00-11.00)12 hours. Please check this correctly...

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anil kumar 13 years AGO

Anil: answer is 8 coins

50-1
20-2
10-1
5-1
2-2
1-1

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~Sandeep~ 13 years AGO

@Koushik: Could you please explain how you got answer as 15.
Refer to reason for yesterday's puzzle which says:
Coins required are 35, 46, 53, 69, 77
so answer is 5
option 10

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~Sandeep~ 13 years AGO

@Koushik: For daily puzzle prize is there only on scoring 96-100 marks

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DIPIN 13 years AGO

@Arpit,
5
front row can have
123, 124, 125,134, 135,

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Koushik Paul 13 years AGO

@Jagat :

The coin which u have selected that is right, but the ques was how many coins are required not how many type of coins required....The ans should be 15...I have choosen this option for today and after declairing the I see that is the right option... got it ?????? Plz reply JAGAT...

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Koushik Paul 13 years AGO

I have a query ? If anyone score top of any week, is there any gift for him/her ??? Or it is available only for scoring 96-100 marks ??? Can any one tell this ???

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arpit gupta 13 years AGO

A photographer will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?
A. 5
B. 6
C. 9
D. 24
E. 36

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