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Ramakrishna to Saraswathy 11 years ago

A man pays off 3/20th of his debt every month. At the end of 6 months his balance debt is 290rs. How much debt (rs) has he cleared off every month?

a) 500 b )450 c) 435 d) 400

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Saraswathy 11 years ago

Let x be the total amount he has to pay
3/20 of x is => 3x/20
For 6 months he might have paid 6*(3x/20) = 9x/10
Balance debt => x - 9x/10 = 290
x = 2900
Every month he cleared 2900*3/20 = 435

Like? Yes (5) | No (2)

Ramakrishna to Saraswathy 11 years ago

13 chairs and 5 tables were bought for 8280rs. If the avg cost of the table will be 1227rs what is the avg cost of a chair?

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Saraswathy 11 years ago

Let C be the total cost of 13 chairs nd T be the total cost of 5 tables
Then
C + T = 8280
Given Avg. cost of table is 1227
Then T/5 = 1227
T = 1227*5 = 6135
Total cost of 5 tables T = 6135
Now C = 8280 - T
C = 8280 - 6135 = 2145
Total cost of 13 chairs = 2145
Avg. cost of 13 chairs ll be => 2145/13 = 165

Ans : 165

Like? Yes (3) | No (2)

Ramakrishna to MANU 11 years ago

40% of the employees of a certain company are men and 75% of the men earn more than 25000rs per year. If 45% of the companys employees earn more than 25000rs per year. What fraction of the women employed by the company earn 25000rs per year or less?

a) 1/4 b) 3/4 c) 1/3 d) 2/11 I NEED COMPLETE SOLUTION PLS HELP ME

Reply Like? Yes | No

~Sandeep~ 11 years ago

Answer: a) 1/4
Reasons:
Assume Total number of Employees in Company = 100
Number of Men = 40, Number of women =60
Number of Men who earn more than 25000 = 75* 40/100 = 30
Number of Total Employee who earn more than 25000 = 45*100/100 = 45
Number of Women who earn more than 25000 = 45-30 = 15
Fraction = 15/60 = 1/4

Like? Yes | No (1)

Harika Punna 11 years ago

I think the answer is 3/4.
Because 15 out of 60 women earn more than 25000, so, 45 women earn 25000 or less than that.
So, answer is 45/60=3/4..

Like? Yes (2) | No

~Sandeep~ 11 years ago

Agree Harika..sorry I didn't realized that we need to find 25000 or less.
Answer should be 3/4

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MANU 11 years ago

let total no of employee=100
male=40
female=60
no of employee having earning more than 25000=45
no of men employee having earning more than 25000=75%of 40=30
so no of women employee having earning less than or equalto 25000 is=60-(45-30)=45
so fraction is 45/60==3/4

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SWARNA 11 years ago

@sandeep: The question is fraction of women who earn 25000 or less not more
So the ans is b)3/4

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Ramakrishna to priyanka 11 years ago

Rohan lends 10000rs in 4 parts. If he gets 8% interest on 2000rs, 15/2% on 4000rs and 17/2% on 1400rs. What percent of interest must he got for the remainder if his avg annual interest is 8.13% ?

a) 10% b)9 % c) 8% d) none I NEED COMPLETE SOLUTION PLS HELP ME

Reply Like? Yes (1) | No

yagnik pandya 11 years ago

Ins is B.
explanation:
8% interest on 2000=160
15/2% interest on 4000=300
17/2% on 1400
So what is R for remaining rupees? ? Is to b found. ..
Total annual interest is 8.13% so total interest will be 813.
Now 160 +300+119=579
So 813 - 579 = 234
Now r can be found because I=234, p=2600, n=2600 by simple interest formula which is >> I = PRN/100
So u wiil get R = 9.
Hope my explanation would help you...

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Ramakrishna to Saraswathy 11 years ago

It cost Rs 1 to photocopy a sheet of paper. However, 2% discount is allowed on all photocopies done after first 1000 sheets. How much will it cost o photocopy 5000 sheets of paper?

a) 3920 rs b) 4900 rs c) 4920 rs d) 3980 rs

Reply Like? Yes | No

MANU 11 years ago

1000+(4000*98/100)=4920

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yagnik pandya 11 years ago

R8 . Agree with abhimanyu kumar

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SWARNA 11 years ago

4920 is the Answer

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Ramakrishna to Saraswathy 11 years ago

(1234)^2+(1230)^2 / 4+(1232)^2 =?

a) 2 b) -2

Reply Like? Yes | No (3)

Saraswathy 11 years ago

(1234)^2+(1230)^2 / 4+(1232)^2
((1230+4)^2 + 1230^2)/(2^2 + (1230+2)^2)
(1230^2+4^2+2*1230*4+1230^2/(4+1230^2+2^2+2*1230*2)
[2*(!230)^2+16+8*1230] / [1230^2 + 8 + 4*1230]
2[1230^2 + 8 + 4*1230] / [1230^2 + 8 + 4*1230]
= 2

Ans : (a) 2

Like? Yes (3) | No (5)

Ramakrishna to Saraswathy 11 years ago

If a two digit number is 4 times the sum it is also 2 times the product of the digits of the number then this number is?

a) 24 b) 36

Reply Like? Yes (1) | No (2)

Navpreet Singh 11 years ago

36
3+6=3*6
4*9=36

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Naznin 11 years ago

3+6=9;
9*4=36;
also, 3*6=18;
3+6=9*2=18......

Like? Yes (1) | No

Ramakrishna to Saraswathy 11 years ago

For what values of k , equation x^2+2(k-4)x+2k=0 has equal roots?

a)2,8 b)2,6

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SAURADIPTA SADHU 11 years ago

a)2,8
4(k-4)^2-8k=0
(k-4)^2-2k=0
k^2-10k+16=0
(k-2)*(k-8)=0
So, k=2,8

Like? Yes (1) | No

priyanka 11 years ago

as we knw that whn that condition roots are equal D=b^2-4ac and D=0
b^2=4ac
(2(k-4))^2=4*2k
k^2-10k+16=0
k=2,8
answer a)2,8

Like? Yes (2) | No

Ramakrishna to Saraswathy 11 years ago

3men, 4women, 6children can complete a work in 7days. A women does double the work a man does and a child does half the work a man does . How many women alone can complete this work in 7days?

a)7 b)8

Reply Like? Yes (3) | No

Devendra Marghade 11 years ago

7 Women

If 1 day work of 1 Man, 1 Woman & 1 Children is (1/M) , (1/W) & (1/C) respectively
Then 1 day work of 3 Men, 4 Women & 6 Children =(3/M)+(4/W)+(6/C)= 1/7 -----(i)
Given women does double the work a man, so (2/M)=(1/W) or 1/M =1/2W ----(ii) and
child does half the work a man, so (1/2M) =1/C ,so from (ii), (1/C)=(1/4W) ---(iii)
Eqn. (i) becomes, (3/2W)+(4/W)+(6/4W)= 1/7 , On solving, W=49
1 Woman can complete the work in 49 days
So to complete the work in 7 days 49/7= 7 women are required.

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Ramakrishna to Saraswathy 11 years ago

pls send the website of online arithmetic problems for daily practice

and send online General Knowledge website for practice

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Ramakrishna to Saraswathy 11 years ago

If 5/x+6y=13 and 3/x+4y=7, find the value of y?

Reply Like? Yes (1) | No

Saraswathy 11 years ago

5/x + 6y = 13
3/x + 4y = 7
Lets take a=1/x... Then the 2 eqns ll become
5a + 6y = 13 --->(1)
3a + 4y = 7 --->(2)
(1) - (2) =>
2a + 2y - 6 = 0 => a + y - 3 = 0
a = 3 - y
5(3 - y) + 6y = 13
15 - 5y + 6y = 13
y = -2
a = 3 - y => 3 - (-2) => a = 5
1/x = 5 => x = 1/5

Ans : X = 1/5, Y = -2

Like? Yes (6) | No

Ramakrishna to Saraswathy 11 years ago

A man has to pay 975rs in yearly instalments and each instalment is less than the earlier one by 5rs. The amount of first instalment is 100rs. In what time the entire amount will be paid?

a)15 b)12 I need complete solution pls help me

Reply Like? Yes (1) | No

Saraswathy 11 years ago

First installment = 100
sec ll be 95, third ll be 90 nd so on...
So 100+95+90+85+.... = 975
a = 100, d=-5, Sn=975,
Sn=n[2a+(n-1)*d)/2
975 = n[2(100)+(n-1)*(-5)]/2
n^2 - 41n + 390 = 0
Solving the above eqn ll give n=15 (or) n=26...
Given options are 15 nd 12... So n value is 15...

Ans : (a) 15

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Ramakrishna to Saraswathy 11 years ago

The radius of a circle is 13cm and AB is a chord which is at a distance of 12cm from the centre. The length of the chord is?

a) 10cm b) 8cm

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Saraswathy 11 years ago

AB is a chord...
Let O be the center of circle nd M be the mid-point of the chord AB...
Then OM = 12cm, OB = 13cm, AM=MB , AB=AM+MB
Apply Pythagoras theorem
(OB)^2 = (OM)^2+(MB)^2
(MB) ^2 = (OB)^2-(OA)^2
(MB)^2 = (13)^2 - (12)^2 => 169-144 = 25
MB = 5
AB = 5+5=10

Ans : (a) 10cm

Like? Yes (2) | No

Ramakrishna to Saraswathy 11 years ago

Goods were bought for 600rs and sold the same day for 688.50rs at a credit of 9months and thus gaining 2%. The rate of interest per annum is?

a) 50/3% b)49/3%

I need complete solution plz help me

Reply Like? Yes (2) | No

Saraswathy 11 years ago

It means after 9 months he will get 688.5 rs from buyer

1.02x=688.5

x=675

675 is the price after 9 months

interest=675-600=75 rs

600*r*(9/12)*1/100=75

r= 16 2/3 % => r=50/3%

Ans : (a) 50/3%

Like? Yes (1) | No

Ramakrishna 11 years ago

Goods were bought for 600rs and sold the same day for 688.50rs at a credit of 9months and thus gaining 2%. The rate of interest per annum is?

a) 50/3% b)49/3%

I need complete solution plz help me

Reply Like? Yes | No

Ramakrishna to Saraswathy 11 years ago

A merchant has 50kgs of sugar part of which he sells at 15% profit and the rest at 20% profit. He gains 17% on the whole. Find how much is sold at 15% profit?

a)30kg b)20kg

i need complete solution pls help me

Reply Like? Yes (3) | No (1)

dileep kumar 11 years ago

assume that 1kg sugar=10rs
given that,
overall profit =17%
17% of 500=85
then 50kg sugar=50*10=500

given 15% on one part =30kg=30*10/kg=300rs
15%of 300=45/-
the remaining part=20kg
20%of 200=40/-
total=30kg+20kg=15% of 300+20% of 200=45+40=85

so one part=30kg and remaining part=20kg

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Ramakrishna to sravya 11 years ago

Reply Like? Yes (1) | No (1)

harsha ramrao jumde 11 years ago

Use alligation rule
15 20
17
3 2
so the ratio is 15:20=3:2
(3/5)*50=30

Like? Yes (3) | No (1)

Ramakrishna to Saraswathy 11 years ago

A person invests money in 3 different schemes for 6 yrs 10yrs and 12yrs at 10%, 12%, 15% simple interest respectively. At the completion of each scheme he gets the same interest. The ratio of his invest is? I need complete solution. plz help me

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Saraswathy 11 years ago

Let the money invested in each scheme be x, y, z
SI = p*n*r/100
SI of 3 schemes ll be => x*6*10/100 , y*10*12/100, z*12*15/100
Ratio of SI ll be => 3x/5 : 6y/5 : 9z/5
=> 3x : 6y : 9z
Ratio of SI of 3 schemes => x : 2y : 3z
Given he gets the same interest on all the schemes ... So x=2y=3z
x = 3z
y = 3z/2
z = z
Ratio of their investments ll be => 3z : 3z/2 : z
=> 6z : 3z : 2z
Ans : 6 : 3 : 2

Like? Yes (4) | No

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