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ER. NAVEEN KUMAR Profile page        View Public Wall My Profile Page

ashalata majhi    9 years ago
hello..i want ur help
Reply Like? Yes (1) | No   
SREEKANTH REDDY CHAKRI   9 years ago
hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
Like? Yes (1) | No   
Ramakrishna    9 years ago
thanks u........................
Reply Like? Yes (1) | No   
RASHMI KUMARI   9 years ago
thank u for ur amazing solution...
Like? Yes (1) | No   
Ramakrishna    10 years ago
Q: find the series? UPI,----, ODP, MBQ, IAW. I NEED COMPLETE SOLUTION PLS HELP ME
Reply Like? Yes (3) | No   
NAVEEN KUMAR   10 years ago
ans-SHJ
for details. go to the
url "https://mega.co.nz/#!B0MxVZKI!5JuQ9h1lSeG2W6fQsPzf5FIdaDWSfoWakVlqvwClpdo"
& download the soln image.
Like? Yes (4) | No (1)  
Ramakrishna    10 years ago
Q: Find the series 9, 19, 40, ---, 146 I NEED COMPLETE SOLUTION PLS HELP ME

a) 83 b) 69 c) 79
Reply Like? Yes (41) | No (9)  
SUBHASH TULSYAN   10 years ago
bro i think the last term of the question is incorrect
i hv explained it as follows:
9=(9*2^0)+(2^1-(2+0))
19=(9*2^1)+(2^2-(2+1))
40=(9*2^2)+(2^3-(2+2))
83=(9*2^3)+(2^4-(2+3)) & so on
so its n term will be
n=(9*2^(n-1))+(2^n-(2+(n-1)))
Like? Yes (8) | No (6)  
sreenivas reddy   10 years ago
ans:83 9*2=18+1=19,
19*2=38+2=40,
40*2=80+3 = 83
Like? Yes (11) | No (13)  
ved prakash   10 years ago
how to preparing for amcat in data structure
Like? Yes (3) | No (5)  
MANISH KUMAR SINGH   10 years ago
Ans is 69
Pattern is square of Prime no + multiple of 5
Like? Yes (27) | No (5)  
sreekala   10 years ago
9*2+1=19
19*2+2=40
40*2+3=83
83*2+4=170
Like? Yes (6) | No (9)  
surya   10 years ago
2*2 + 5 = 9
3*3+10 =19
5*5+15 =40
7*7+20 =69
11*11 +25 =146
Like? Yes (53) | No (3)  
APPIKONDA SANTOSH NAIDU   10 years ago
9*2+1=19
19*2+2
40*2+3
so answer is 83 bro
Like? Yes (2) | No (8)  
srinath T   10 years ago
9,
(9+9 +1)=19
(19+19 +2) =40
,(40+40 +3).=83
Like? Yes (2) | No (4)  
mohamed rasik   10 years ago
hi bro the answer is 83
Like? Yes (1) | No (4)  
A M ANKIT KALLURAYA   10 years ago
9,9*10+1=19,19*2+2=40,40*2+3=83
Like? Yes (3) | No (3)  
Anmol saraogi   10 years ago
the answer will 83 because 9*2+1=19
19*2+2=40
40*2+3=83
Like? Yes | No (3)  
Rabi Kumar   10 years ago
2*2+5=9
3*3+10=19
5*5+15=40
7*7+20=69
11*11+25=146
ans:69
Like? Yes (11) | No   
kundan   10 years ago
(Prime no)^2 + n5 ,
n=1,2,3,4,5,6.........)

2x2 + 5 = 9
3x3+10 =19
5x5+15 =40
7x7+20 =69
11x11 +25 =146

so ans is 69
Like? Yes (12) | No   
amit kumar singh   10 years ago
a it is like 9*2+1=19 which is next term
and 19*2+2=40 therd term
so the next term will be 40*2+3=83
Like? Yes | No (6)  
RACHANA   10 years ago
83 because
9=9*2^0+(2^1-(2+0))
19=9*2^1+(2^2+(2+1))
40=similar
83="
146="
Like? Yes | No (4)  
abhishek narayan   10 years ago
ans b)69
use square of prime numbers + multiple of 5.
2^2 + 5 =9
3^2 + 10=19
5^2 + 15=40
7^2 + 20=69
11^2 + 25=146
Like? Yes (3) | No   
venkat   8 years ago
The answer is
square of prime + multiple of 5
2*2+5=9
3*3+10=19
5*5+15=40
7*7+20=69
11*11+25=146
Like? Yes (5) | No   
NAVEEN KUMAR    11 years ago
How many zeroes does 100^1* 99^2 *98^3* 97^4 ......2^{99} *1^{100} have?
Reply Like? Yes (5) | No (1)  
arun kumar   11 years ago
the answer is 1124
Like? Yes (1) | No   
NAVEEN KUMAR    11 years ago
How many positive integers less than 10,000 are there in which the sum of the digits equals 5?
Reply Like? Yes | No   
Anand Dwivedi   11 years ago
I believe the answer to be C: 56.

Basically, the question asks how many 4 digit numbers (including those in the form 0XXX, 00XX, and 000X) have digits which add up to 5. Think about the question this way: we know that there is a total of 5 to be spread among the 4 digits, we just have to determine the number of ways it can be spread.

Let X represent a sum of 1, and | represent a seperator between two digits. As a result, we will have 5 X's (digits add up to the 5), and 3 |'s (3 digit seperators).

So, for example:

XX|X|X|X = 2111
||XXX|XX = 0032

etc.

There are 8C3 ways to determine where to place the separators. Hence, the answer is 8C3 = 56.
Like? Yes | No   
NAVEEN KUMAR   11 years ago
mr. anand i don't give any option
ur ans is copy from url
http://gmatclub.com/forum/how-many-positive-integers-less-than-10-000-are-there-in-85291.html
Like? Yes | No   
  • ER. NAVEEN
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NAVEEN KUMAR Bihar
Naveen kumar (M)
  • Total Points 1358
  • Join 11 years ago
M4 Score
85
Score from best 50 Questions
  • Attempted 50     
  • Date Points     
  • 26 Aug 14 17
  • 02 Sep 14 16
  • 03 Sep 14 20
  • 10 Sep 14 16
  • 11 Sep 14 17
  • 15 Sep 14 20
  • 16 Sep 14 18
  • 19 Sep 14 18
  • 22 Sep 14 20
  • 23 Sep 14 17
  • 24 Sep 14 17
  • 29 Sep 14 18
  • 30 Sep 14 18
  • 06 Oct 14 19
  • 09 Oct 14 18
  • 22 Oct 14 18
  • 23 Oct 14 20
  • 24 Oct 14 19
  • 27 Oct 14 20
  • 28 Oct 14 16
  • 29 Oct 14 18
  • 03 Nov 14 20
  • 04 Nov 14 17
  • 05 Nov 14 17
  • 06 Nov 14 16
  • 19 Nov 14 16
  • 24 Nov 14 19
  • 15 Oct 15 15
  • 19 Oct 15 15
  • 20 Oct 15 15
  • 21 Oct 15 15
  • 28 Oct 15 15
  • 30 Oct 15 15
  • 02 Nov 15 15
  • 13 Nov 15 15
  • 16 Nov 15 15
  • 17 Nov 15 16
  • 18 Nov 15 15
  • 19 Nov 15 15
  • 25 Nov 15 15
  • 01 Dec 15 15
  • 07 Dec 15 19
  • 09 Dec 15 15
  • 10 Dec 15 18
  • 11 Dec 15 17
  • 14 Dec 15 16
  • 18 Dec 15 17
  • 28 Dec 15 19
  • 30 Dec 15 19
  • 31 Dec 15 18
  • Total 854     
  • M4 Score854 / 10 = 85     
meghnad saha institute of technology
Today's Puzzle Report
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  • Total Puzzle Points 1385
Placement Puzzle Report
  • Question Ask 10
  • Best Solution 2
  • Solution 58
Last Update 9 years ago

Best 2 Engineers From
meghnad saha institute of technology

NAVEEN KUMAR Bihar
Naveen kumar (M)
  • Total Points 1358
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M4 Score
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Satyaki West Bengal
Satyaki (M)
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