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ER. Neha gupta Profile page        View Public Wall My Profile Page

Syed Farhaz Ali    9 years ago
What is the remainder when 6^17+117^6 is divided by 7 ?
a) 1 b) 6 c) 0 d) 3
Reply Like? Yes (1) | No (1)  
neha gupta   9 years ago
To solve this question , first break the LCM i.e. find the remainder when 6^17 is divided by 7
and then find remainder when 117^6 is divided by 7 :
as follows:
See, if even power of 6 is divided by 7, remainder is 1 and
if odd power of 6 is divided by 7, remainder is 6
so here power of 6 is 17(odd) so its remainder is 6
Now for 117,
if even power of 117 is divided by 7, remainder is 4
if odd power of 117 is divided by 7, remainder is 5
so here power of 117 is 6(even) so remainder is 4
now add both the remainders obtained i.e. 6 + 4 = 10
and when 10 is divided by 7 remainder is 3,
so its answer is 3 (option d).
Like? Yes (1) | No (2)  
Rishu   9 years ago
c) 0

(6^17+117^6)=(7-1)^17+(112+5)^6=(-1)^17+5^6=(-1)+15625=15624=0mod7

so (6^17+117^6)=0mod7

Thus the remainder when (6^17+117^6) is divided by 7 is 0
Like? Yes (2) | No   
Ramakrishna    9 years ago
Q: 1^1/2: 3^3/4:: 1^2/3: x. then the value of x is ?

a) 3^1/6 b) 4^1/6
Reply Like? Yes (1) | No   
Ramakrishna    9 years ago
Thanks you neha................
Reply Like? Yes (1) | No (1)  
neha gupta   9 years ago
any time Parusharam
Like? Yes (1) | No   
Ramakrishna    9 years ago
Q: what is 5^2/3 -4^1/6 + 2^3/4 -1^1/4 is ?

a) 4 b) 3 c) non
Reply Like? Yes (1) | No   
Satnam Singh Chahal    9 years ago
hi lets be frnd on fb if u r intersted
Reply Like? Yes | No   
neha gupta    10 years ago
a+b+c+d=ac=19
a=1,c=9
b+d=9,b*d=126/9=14
therefore,d=7 and b=2
or d=2,b=7
d-a=6 or 1
Reply Like? Yes | No   
Gugulothu vijaykumar   9 years ago
hai how are you medam
Like? Yes | No   
  • ER. Neha
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neha gupta Uttar Pradesh
Neha gupta (F)
  • Total Points 1289
  • Join 12 years ago
M4 Score
86
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  • Total 868     
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