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radhe 3 years ago

Hii,

There are 100 men in town. Out of which 85% were married, 70% have a
phone, 75% own a car, 80% own
a house. What is the maximum number of people who are married, own a
phone, own a car and own a house ?

Reply Like? Yes | No

KESHAV MANDAL 3 years ago

>% not married 15
>% no phone 30
>% no car 25
>% no house 20
>so 15 +30+25+20=90
>so 100-90=10 min with phone,car,house,married and house
>now they could overlap but since minimum possible asked so 10.I think
>am right.

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Akanksha Mishra to RAKESH 5 years ago

integration of
(2x^12 + 5x^9)/(x^5 + x^3 +1)

Reply Like? Yes (2) | No

RAKESH 5 years ago

divide (2x^12 + 5x^9) by (x^5 + x^3 +1) & then use partial fraction

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Akanksha Mishra to RAKESH 5 years ago

plz solve it
intregation of (cos5x+ cos4x )/(1 - 2cos2x)

Reply Like? Yes (1) | No

RAKESH 5 years ago

(cos5x+ cos4x )/(1 - 2cos2x)

= 2*cos(9x/2)*cos(x/2) / (3 - 4cos^2x)

= -2cosx*cos(9x/2)*cos(x/2) / cos3x

i think its itegration can't be evaluated or can be in terms of inverse hyperbolic fns
is the qn right??

Like? Yes (2) | No

Akanksha Mishra 5 years ago

ya que is right it think cos5x or cos4x is to be argest like cos5x = cos3x + cos2x .....this make the solution easy can u try one more time ?????

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RAKESH 5 years ago

tell its answer......i will try

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Akanksha Mishra 5 years ago

sorry i hvn't..........

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RAKESH 5 years ago

ok.....
u can't find integration of each integrals.

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Akanksha Mishra 5 years ago

thanks rakesh i hv solved

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RAKESH 5 years ago

can u post the soln, how u solved?

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Akanksha Mishra 5 years ago

solve it
intregation of (cos5x+ cos4x )/(1 - 2cos2x)

Reply Like? Yes (2) | No

vineysagar 5 years ago

hiiii akansha ... plz help me to amcat exam . plz send me some important short tricks formula for numbers,, profit lose,squares and data assumption methods on vineysagar2@gmail.com or on fb dudesuper333@gmail.com plzzz send , very urgent.....

Reply Like? Yes (2) | No

Akanksha Mishra 5 years ago

sorry @vinay i haven't

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Akanksha Mishra to RAKESH 5 years ago

Dear Rakesh ,
I am again in confussion please slove it as early as possible

x^1/2 + y = 7
x + y^1/2 = 11

prove that x = 9 and y = 4

Reply Like? Yes (5) | No

RAKESH 5 years ago

âˆšx + y = 7
x + âˆšy = 11

âˆšx + y = 7
=> x = (7-y)^2 = 49 + y^2 - 14y

x + âˆšy = 11
=> y = (11-x)^2
=> y = (11 - 49 - y^2 + 14y)^2
=> y = (y^2 -14y +38)^2
=> y = y^4 + 196y^2 + 1444 -28y^3 -1064y + 76y^2
=> y^4 - 28y^3 + 272y^2 - 1065y + 1444 = 0
at y=4, above eqn satisfies
=> (y-4)*(y^3 -------) = 0
=> y = 4
so, x = 9

Like? Yes | No (2)

Akanksha Mishra 5 years ago

NO Rakesh we have to prove that x= 9 and y=4 ....
we can't satisfy any equation to put the value of x and y...
.imagine we don't know the original value of x and y ,now prove that

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RAKESH 5 years ago

for ex
we have to solve x^5 + x - 2 = 0
here we see that at x = 1 , above eqn satisfies
so, from remainder theorem, (x-1) is a factor of the eqn
now divide x^5 + x - 2 by (x-1)
=> (x-1)*(x^4 ---some terms) = 0
=> x = 1
the same thing i have done in the ans.

otherwise
x^1/2 + y = 7
x + y^1/2 = 11

let x = a^2 & y = b^2

a + b^2 = 7 & a^2 + b = 11
subtract
(a^2-b^2)+(b-a) = 4
=> (a-b)(a+b-1) = 4 = 1*4 = 2*2 = 4*1 (for integral values)

if a-b = 1 , a+b-1 = 4 => a = 3, b = 2
if a-b = 2 , a+b-1 = 2 => a = 5/2 , b = 1/2 doesn't satisfy eqn
if a-b = 4 , a+b-1 = 1 => a = 3 , b = 2

so, a = 3 , b = 2
=> x = 9 , y = 4

Like? Yes (2) | No

Akanksha Mishra 5 years ago

I got it Thankyou @Rakesh for your best solution.......

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Akanksha Mishra to RAKESH 5 years ago

Find the maximum slope of the curve
f(x) = 2x + 3x^2 - x^3 - 27
Can u suggest me y are we taking f''(x) = 0 and when should we take three step f'''(x) plz clarify the concept i'm confused ...

Reply Like? Yes (1) | No

Anurag Kumar Singh 5 years ago

Hi Akanksha,

f'(x) = -3x^2 + 6x + 2
now for slope of f(x) to be maximum, the value of f'(x) must me maximum.
so, f'(x) is a quadratic equation with curve bent downwards. So, the local maxima will be the global also.
now, calc f''(x) = 0.
you get the point of global maxima and hence the ans.....

slope of f(x) is maximum at x = 5.

plz tell me if not understood.
ID: anurag160991@gmail.com

Like? Yes (1) | No

RAKESH 5 years ago

f(x) = 2x + 3x^2 - x^3 - 27

to find slope of a function f(x) find f'(x)
slope = f'(x) = 2 + 6x - 3x^2 = g(x) let

now we have to find maxm of g(x)
g'(x)= 0 gives the point of maxm/minm
if g''(x) > 0 then g(x) has mimm
if g''(x) < 0 then g(x) has maxm

f''(x) = (6 - 6x) = 0 => x = 1

f'''(x) = -6 < 0 => f'(x) has a maxm at x = 1

maxm slope = f'(1)= 2 + 6 - 3 = 5

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Akanksha Mishra 5 years ago

Thankyou @Rakesh and @Anurag

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Akanksha Mishra 5 years ago

Hey frnds can you suggest the defination of infinitive related to maths?????

Reply Like? Yes (1) | No

Vijay Menaria 5 years ago

denotes a quantity or set larger than any finite number

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Akanksha Mishra 5 years ago

Hey frnds can you suggest the define of infinitive related to maths?????

Reply Like? Yes (1) | No

Akanksha Mishra 5 years ago

Join group "I love maths" on fb i want more maths lovers....
https://www.facebook.com/groups/228673120655444/

Reply Like? Yes (4) | No (1)

Akanksha Mishra 5 years ago

Join the Group "I Love Maths" on facebook...........if u love maths

Reply Like? Yes (2) | No

sohan saini 5 years ago

i m new to m4maths.........and i love maths

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nirmal kumar saini 5 years ago

can you tell me where and when the off campus recruitment drives are going on recent times?

Reply Like? Yes (9) | No

Akanksha Mishra 5 years ago

Sorry i am not a student of college

Like? Yes (1) | No (1)

Raju 5 years ago

here value of only 1st,3rd,5th and so on are written in code
for Rahul: R=18 H=8 L=12 so code become=18812
So for praveen= P=16 A=1 E=5 N=14 so code=161514

Reply Like? Yes | No

Akanksha Mishra 5 years ago

Hi frnds today .. today's puzzle is incomplete.Am I right ?

Reply Like? Yes (2) | No (7)

Akanksha Mishra 5 years ago

can You suggest me.. how can I get the question of Last Week which had asked in Today Puzzle?

Reply Like? Yes (2) | No

Akanksha Mishra 5 years ago

Find the number of 4- letter words,that can be formed from the letters of the word "ALLAHABAD"

Reply Like? Yes (1) | No

tanmay vyas 5 years ago

9P4; if rep is nt allwd.

Like? Yes | No (4)

mahesh 5 years ago

9!/(4!*2!)
L occurs 2 times
a occurs 4 times

Like? Yes (3) | No (1)

Akanksha Mishra 5 years ago

Please solve this question....
There are n person sitting round a table
find the number of different ways in which 3 person can be selected so that no two are neighbors...
Answer hint : 1/6*n(n-4)(n-5)

Reply Like? Yes | No

Akanksha Mishra 5 years ago

PLease solve it as early as possible
A ladder rests against a wall at angle A to the horizontal,if foot is pulled away from the wall through a distance 'a' so that it slides a distance b down the wall making an angle B with the horizontal
show that
a/b = cosA - cosB/SinB - SinA

Reply Like? Yes (2) | No

Syed Faizan Haider 5 years ago

let l be the length of ladder then l=(x^2+y^2)
after pulling,disatances will be (x+a)& (y-b)
1st case
x/sin(90-A)= y/sinA = l/sin90 => sinA=y/l & cosA=x/l

2nd case
(x+a)/sin(90-B)=(y-b)/sinB = l/sin90 => sinB=(y-b)/l & cosB=(x+a)/l

so (cosA-cosB)/(SinB-SinA)=[ x/l - (x+a)/l ]/[(y-b)/l - y/l] = a/b

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GEETHA KALYANI 5 years ago

Hi,
Can you tell me how numbers are given to alphabets in the question days+too=short

Reply Like? Yes | No

VIKRAM KUMAR 5 years ago

@tarunpreet:vikkumatre18@gmail.com thank you bhai....

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Akanksha mishra (F)

Total Points 1311
Join 6 years ago

M4 Score

Score from best 50 Questions

Attempted 50
Date Points

06 Dec 13 19
10 Dec 13 18
16 Dec 13 16
19 Dec 13 17
25 Dec 13 17
30 Dec 13 19
07 Jan 14 18
09 Jan 14 17
13 Jan 14 20
14 Jan 14 19
20 Jan 14 17
22 Jan 14 17
28 Jan 14 16
30 Jan 14 16
03 Feb 14 19
10 Feb 14 19
11 Feb 14 17
14 Feb 14 18
17 Feb 14 18
18 Feb 14 17
21 Feb 14 17
25 Feb 14 17
27 Feb 14 17
03 Mar 14 17
10 Mar 14 20
11 Mar 14 18
12 Mar 14 18
17 Mar 14 20
18 Mar 14 16
20 Mar 14 19
21 Mar 14 15
24 Mar 14 18
25 Mar 14 17
26 Mar 14 15
28 Mar 14 15
31 Mar 14 15
01 Apr 14 15
18 Apr 14 18
24 Apr 14 19
25 Apr 14 15
05 May 14 17
12 May 14 16
14 May 14 15
02 Jun 14 16
03 Jun 14 15
04 Jun 14 19
14 Jul 14 15
22 Dec 14 15
29 Dec 14 15
02 Jan 15 15

Total 853
M4 Score853 / 10 = 85

Today's Puzzle Report

Puzzle Attempts99
Total Puzzle Points 1301

Placement Puzzle Report

Question Ask 15
Best Solution 24
Solution 101

Last Update 1 year ago

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