Maximum numbers that can be formed using all the 4 digits 6, 4, 8, 1 without repetition which is divisible by 9

• zero as A number is divisible by 9 if sum of digits of the number is divisible by 9.
  Here 6+4+8+1=19 which is not divisible by 9.
• 13 years agoHelpfull: Yes(43) No(4)
• none...
  
  for any number to be divisible by 9, the sum of the digits of that number should be factor of 9
  6+4+8+1=19 is not a factor of 9. so it is not divisible by 9.
• 13 years agoHelpfull: Yes(11) No(0)
• 0
  becuase the sum of 6,4,8,1 is 19 and 19 is not divisible by 9
• 13 years agoHelpfull: Yes(10) No(3)
• any number formed by 64981 not divisible by 9
• 13 years agoHelpfull: Yes(5) No(3)
• ans is 0 as the sum of the numbers is not divisible by 9
• 13 years agoHelpfull: Yes(4) No(1)
• zero.....
  6+4+9+1=19 not divisible by 9
  
• 13 years agoHelpfull: Yes(3) No(0)
• Zero as sum of digits (19) is not divisible by 19.
• 13 years agoHelpfull: Yes(2) No(0)
• 24
  because of :4p4 =24
  
• 13 years agoHelpfull: Yes(2) No(19)
• i think 8.
  4 digit no.s= 0 (as sum of digits 6+4+8+1=19)
  3 digit no.s=6(as 6+4+8=3!=6)
  2digit no.s=2(8+1)
• 8 years agoHelpfull: Yes(1) No(0)
• 6+4+8+1
  = 19 so it is not divisible by 9
• 6 years agoHelpfull: Yes(0) No(0)