Maximum numbers that can be formed using all the 4 digits 6 4 8 1
without repetition and which is divisible by 9

• 0 bcoz for divisible by 9 sum of numbers must be divisible by 9 which in this case is 19 so no number possible
• 13 years agoHelpfull: Yes(16) No(8)
• a number must b divisible by 9 when summation of it's digits will b divisible by 9.here given digits r 6,4,8,1.
  6+4+8+1=19
  19 cant b divisible by 9.
  so no number can b formed.
  ans is 0.
• 13 years agoHelpfull: Yes(12) No(8)
• 0
• 13 years agoHelpfull: Yes(11) No(5)
• 0
• 13 years agoHelpfull: Yes(9) No(5)
• one digit number = 0 numbers
  two digit number= 2 numbers
  three digit number= 6 numbers
  four digit number = 0 numbers
• 13 years agoHelpfull: Yes(1) No(2)
• 81^64
  81^2=6561,whose unit digit is 1 & divisible by 9
  81^4=43046721,unit digit also 1 & divisible by 9
  similarly 81^64 is also divisible by 9.
• 13 years agoHelpfull: Yes(1) No(12)
• zero. because sum of digits is 19 which is not divisible by 4
• 10 years agoHelpfull: Yes(1) No(0)