Syntel
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Numerical Ability
Permutation and Combination
Maximum numbers that can be formed using all the 4 digits 6 4 8 1
without repetition and which is divisible by 9
Read Solution (Total 7)
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- 0 bcoz for divisible by 9 sum of numbers must be divisible by 9 which in this case is 19 so no number possible
- 14 years agoHelpfull: Yes(16) No(8)
- a number must b divisible by 9 when summation of it's digits will b divisible by 9.here given digits r 6,4,8,1.
6+4+8+1=19
19 cant b divisible by 9.
so no number can b formed.
ans is 0. - 14 years agoHelpfull: Yes(12) No(8)
- 0
- 14 years agoHelpfull: Yes(11) No(5)
- 0
- 14 years agoHelpfull: Yes(9) No(5)
- one digit number = 0 numbers
two digit number= 2 numbers
three digit number= 6 numbers
four digit number = 0 numbers - 14 years agoHelpfull: Yes(1) No(2)
- 81^64
81^2=6561,whose unit digit is 1 & divisible by 9
81^4=43046721,unit digit also 1 & divisible by 9
similarly 81^64 is also divisible by 9. - 14 years agoHelpfull: Yes(1) No(12)
- zero. because sum of digits is 19 which is not divisible by 4
- 10 years agoHelpfull: Yes(1) No(0)
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