if x + y = 1/x^2 + 1/x^3
then y(1/2) - y(1) will be
here y(n) is the value of y at x = n

• y(1/2)-y(1)=21/2 ans.
  sol:-
  y={(1+x)-x^4}/x^3
  y(1/2)=23/2
  y(1)=1
  hence,y(1/2)-y(1)=21/2 ans.
• 12 years agoHelpfull: Yes(7) No(1)
• x + y = 1/x^2 + 1/x^3
  y = 1/x^2 + 1/x^3 -x
  y(1) = 1+1-1=1
  y(1/2) = 4+8-1/2 = 23/2
  y(1/2) - y(1) = 23/2 -1 = 21/2 = 10.5
  
• 12 years agoHelpfull: Yes(5) No(5)