IBM
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Numerical Ability
LCM and HCF
Let p and q be two prime numbers such that p is greater than q. If 319 is their LCM then the difference of thrice of q and p is:
Read Solution (Total 8)
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- We know that, HCF of two prime numbers is 1.
Product of HCF and LCM = 1 x 319 = 319.
Remember that, Product of two number = Product of their HCF and LCM
pq = 319
Now, co-primes with product 319 are (1,319) and (29,11)
Since p > q, p = 29 and q = 11
Then 3q - p = 3 - 29 = 4. - 9 years agoHelpfull: Yes(43) No(2)
- p and q are prime numbers so no would be 11*29=319
acc to q 3q-p=3*11-29=4; - 9 years agoHelpfull: Yes(8) No(0)
- Ans:4
By taking LCM of 319 we get 11,29
p>q so p=29 and q=11
3q-p=3*11-29=4 - 9 years agoHelpfull: Yes(3) No(0)
- Answer : c)4.
Solution :
We know that, HCF of two prime numbers is 1.
Product of HCF and LCM = 1 x 319 = 319.
Remember that, Product of two number = Product of their HCF and LCM
pq = 319
Now, co-primes with product 319 are (1,319) and (29,11)
Since p > q, p = 29 and q = 11
Then 3q - p = 3 - 29 = 4.
- 9 years agoHelpfull: Yes(1) No(0)
- p and q are prime numbers. So, HCF of p & q is 1. Now pq = HCF x LCM=319. Again 319=11 x 29. So, p=29 and q=11 since p> q . Now 11 x 3 - 29 = 4. 4 is answer
- 9 years agoHelpfull: Yes(0) No(0)
- p=29 and q=11 so 3q-p=4
- 9 years agoHelpfull: Yes(0) No(0)
- lcm is 319 then their product is 29,11 these two are primes the diff is 18
- 8 years agoHelpfull: Yes(0) No(1)
- We know that, HCF of two prime numbers is 1.
Product of HCF and LCM = 1 x 319 = 319.
Remember that, Product of two number = Product of their HCF and LCM
pq = 319
Now, co-primes with product 319 are (1,319) and (29,11)
Since p > q, p = 29 and q = 11
Then 3q - p = 3 - 29 = 4. - 7 years agoHelpfull: Yes(0) No(0)
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