Let p and q be two prime numbers such that p is greater than q. If 319 is their LCM then the difference of thrice of q and p is:

• We know that, HCF of two prime numbers is 1.
  Product of HCF and LCM = 1 x 319 = 319.
  Remember that, Product of two number = Product of their HCF and LCM
  pq = 319
  
  Now, co-primes with product 319 are (1,319) and (29,11)
  Since p > q, p = 29 and q = 11
  Then 3q - p = 3 - 29 = 4.
• 9 years agoHelpfull: Yes(43) No(2)
• p and q are prime numbers so no would be 11*29=319
  acc to q 3q-p=3*11-29=4;
• 9 years agoHelpfull: Yes(8) No(0)
• Ans:4
  By taking LCM of 319 we get 11,29
  p>q so p=29 and q=11
  3q-p=3*11-29=4
• 9 years agoHelpfull: Yes(3) No(0)
• Answer : c)4.
  
  Solution :
  
  We know that, HCF of two prime numbers is 1.
  Product of HCF and LCM = 1 x 319 = 319.
  Remember that, Product of two number = Product of their HCF and LCM
  pq = 319
  
  Now, co-primes with product 319 are (1,319) and (29,11)
  Since p > q, p = 29 and q = 11
  Then 3q - p = 3 - 29 = 4.
  
  
• 8 years agoHelpfull: Yes(1) No(0)
• p and q are prime numbers. So, HCF of p & q is 1. Now pq = HCF x LCM=319. Again 319=11 x 29. So, p=29 and q=11 since p> q . Now 11 x 3 - 29 = 4. 4 is answer
• 9 years agoHelpfull: Yes(0) No(0)
• p=29 and q=11 so 3q-p=4
• 9 years agoHelpfull: Yes(0) No(0)
• lcm is 319 then their product is 29,11 these two are primes the diff is 18
• 7 years agoHelpfull: Yes(0) No(1)
• We know that, HCF of two prime numbers is 1.
  Product of HCF and LCM = 1 x 319 = 319.
  Remember that, Product of two number = Product of their HCF and LCM
  pq = 319
  
  Now, co-primes with product 319 are (1,319) and (29,11)
  Since p > q, p = 29 and q = 11
  Then 3q - p = 3 - 29 = 4.
• 7 years agoHelpfull: Yes(0) No(0)