A company has offices in two different buildings. 50% of the copying machines in the first building

and 28% of the copying machines in the second building received preventive maintenance last

month. If 87% of the company’s copying machines are in the first building, what percent of all the

copying machines received preventive maintenance last month?

• 50% of 87 machines is 50*87/100=43.5 and
  28% of 13 machines is 13*28/100=3.64,
  so
  43.5+3.64 =47.14
• 9 years agoHelpfull: Yes(62) No(1)
• Let there are 100 machines.
  So 87 machines are in 1st building. And remaining 13 are in 2nd building.
  Now we know that
  50 percent of machines in 1st building got repair so 50 percent of 87 is(50×87)/100 =43.5
  And 28 percent of 2nd building ie (28×13)/100 = 3.64
  So adding machines of both buildings that are repaired we get (43.5+3.64)=47.14
• 9 years agoHelpfull: Yes(14) No(0)
• 87% of companies machines in building 1
  13 %of ,, ,, ,, 2
  
  let building 1 have 87 machine and building 2 have 13 machine..
  
  so28% of 2nd building got maintenance..
  
  so, 28% of 13= 13* 28/100 = 3.64 ans...
• 9 years agoHelpfull: Yes(2) No(25)
• if we are assuming total 100%.. then
  first building has 87% copying machines..so
  second building has 13% copying machines..then
  50% of copying machines preventive in first building so 50% of 87%
  87*50/100 = 43.5.
  28% of copying machines preventive in second building so 28% of 13%
  28*13/100 =3.6
  so total copying machines received preventive maintance last month is 43.5+3.6 =47.1.
• 9 years agoHelpfull: Yes(2) No(0)
• please any one can submit correct answer for this question
  
• 9 years agoHelpfull: Yes(1) No(0)
• 43.5%
  50% * 87% *x
  where x is total no. of machines
• 9 years agoHelpfull: Yes(0) No(8)