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Maths Puzzle
Q. What is the sum of digits of Number obtain (10^3)^8-8.
Read Solution (Total 5)
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- (10^3)^8-8 = (10^24)-8 = 9999999..... (23 times 9)2
sum of digits = (23*9)+2 = 209 - 12 years agoHelpfull: Yes(5) No(3)
- sum of digits = 209
- 12 years agoHelpfull: Yes(3) No(1)
- ans : 209
- 12 years agoHelpfull: Yes(2) No(2)
- 1
10^3 = 1000
8-8 = 0
(10^3)^8-8 = 1000^0 = 1 - 12 years agoHelpfull: Yes(2) No(5)
- when we substract 8 from 10^24 we get 23 digits ,out of them 23 digits there will be 22 times 9 and one 2
so answer will be 22*9+2=200 - 12 years agoHelpfull: Yes(0) No(0)
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