Employee of a company is in either Department X or Department Y. There are twice as many employees in Department X as in Department Y. The average (arithmetic mean) salary is Rs 25,000 for the employees in Department X and is Rs 35,000 for the employees in Department Y ,then what is the average salary of all the employees ?

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  suppose there are 2y employees in deppt x and y emp. in deptt. y, then
  average salary of all employees = ((2y*25000)+(y*35000))/3y = Rs. 85000/3
• 12 years agoHelpfull: Yes(8) No(1)
• suppose there are 2y employees in deppt x and y emp. in deptt. y, then
  average salary of all employees = ((2y*25888)+(y*35000))/3y = Rs. 85000/3
• 12 years agoHelpfull: Yes(2) No(0)
• X=2Y . ie, 25000=S1/2Y
  35000=S2/Y
  Salary of all= S1+S2/3Y
  
  (25000*2Y+35000Y)/3Y = 85000Y/3Y ; Y= 85000/3
• 7 years agoHelpfull: Yes(0) No(0)