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Maths Puzzle
Let a < 1, b < 1 and consider the infinite G.P's, x= 1+a+a2+...., y= 1+b+b2+...., and z=1+ab+ab2+...., then z=
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- HERE A=1,R=AB
sum of infinite terms=a/1-r=1/1-ab
z=1/1-ab
x=1/1-a==>-a=1/x-1
y=1/1-b==>-b=1/y-1
ab=(1/x-1)(1/y-1)=(1-x)(1-y)/xy
so z=1/(1-ab)
=xy/(xy-(1-x)(1-y)) - 12 years agoHelpfull: Yes(1) No(0)
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