Two finite sets have m and n elements. the number of elements in the power set of first set is 48 more than the total number of elements in the power set of the second set. Then the values of m and n are.

• m=6, n=4
  
  
  pls check
  2^m-2^n=48
  
  there is one possible set of m and n where
  m=6, n=4
  2^6-2^4 = 64-16 = 48
  
  
• 12 years agoHelpfull: Yes(2) No(0)
• TWO sets have m and n elements
  power set of 1st set=2^m
  power set of 2nd set =2^n
  given that 1st have 48 more than power set b
  i.e,
  2^m+48=2^n
  by sub m=6 nd n=4 both r equal so
  m=6 n=4
• 12 years agoHelpfull: Yes(2) No(0)
• Let A and B be the sets with 'm' and 'n' elements respectively.
  Then, the number of elements in their power set are 2^m and 2^n respectively.
  It is given that, 2^m=2^n+48
  2^m-2^n=48
  The above equation contains two unknowns and it can have any number of solutions. so, see the options given and try to put those values in the above equation and the pair which will satisfies the above equation is the answer.
• 12 years agoHelpfull: Yes(1) No(1)