Capgemini
Company
Numerical Ability
Number System
how many 5 digit nos can be formed with digits 1,2,3,4,5,6 which are divisible by 4 and digits not repeated?
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- last 2 digits should is divided by 4 then we can say number is divided by 4
we have 8 ways in filling last 2 blanks 12,16,24,32,36,52,56,64 now we are left with 3 blanks already 2 numbers are taken so there are 4 numbers so 1st blank filled in 4ways,2nd in 3,3rd in 2
so 4*3*2*8=192 - 12 years agoHelpfull: Yes(32) No(3)
- 192 numbers can be formed
Last 2 digits must be 12,16,24,32,36,52,56,64 = 8 ways
Remaining 3 digits in 4*3*2 = 24ways
Total = 24*8 = 192 ways - 12 years agoHelpfull: Yes(18) No(2)
- Test of divisibility by 4 is that the last two digits should be divisible by 4.
1 : When the last 2 digits are 12, i.e., _ _ _ 12 = 4 * 3 * 2 = 24 numbers
2 : When the last 2 digits are 16, there are 24 numbers
3 : When the last 2 digits are 24 there are 24 numbers
4 : When the last 2 digits are 32 there are 24 numbers
5 : When last 2 digits are 36 there are 24 numbers
6 : When last 2 digits are 52 there are 24 numbers
7 : When last 2 digits are 56 there are 24 numbers
8 : When last 2 digits are 64 there are 24 numbers
Total = 8 * 24 = 192 - 12 years agoHelpfull: Yes(4) No(1)
- hello item
- 12 years agoHelpfull: Yes(2) No(0)
- Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
30 + 30 = 4 1
(15 + x) (15 - x) 2
900 = 9
225 - x2 2
9x2 = 225
x2 = 25
x = 5 km/hr.
- 10 years agoHelpfull: Yes(1) No(1)
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