Capgemini
Company
Numerical Ability
Boats and Streams
A motorboat whose speed is 15 kmph in still water goes 30 kmph downstream and comes back in a total of 4hrs 30min the speed of the stream in kmph is
Read Solution (Total 16)
-
- if we read question carefully...the speed of motor boat in downstream = 30 kmph(not 30 km)
therefore, speed of the stream= 30-15
=> 15 kmph
- 12 years agoHelpfull: Yes(41) No(25)
- 5 km/hr.
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
Therefore,
30/(15+x) + 30/(15-x) = 4(1/2)
=> 900/(225-x^2) = 9/2
=> 9x^2 = 225
=> x^2 = 25
=> x = 5
- 12 years agoHelpfull: Yes(32) No(27)
- Speed in Down Stream(Boat+Stream)=30 Kmph
Speed in Still Water=15 Kmph
Speed of The Stream[(Boat+Stream)-Boat]=30-15 = 15 Kmph - 12 years agoHelpfull: Yes(19) No(11)
- Let the speed of the stream be x km/hr. Then,
speed downstream =(15 + x)km/hr
Speed upstream = (15 - x) km/hr.
Time= Distance/speed
30/15+x + 30/15-x = 9/2
On solving, 900/225-x^2 = 9/2
x^2=25
x=5km/hr
x = 5 km/hr. - 12 years agoHelpfull: Yes(15) No(10)
- 5 kM/HR
Let the speed of the sream is x km/hr
speed of upstream=15+x
speed of down stream=15-x
30/15+x+30/15-x=9/2
solving this we get x^2=25
x=5 km/hr - 12 years agoHelpfull: Yes(11) No(22)
- 5km/hr....let speed of stream be x then 30/(15-x)+ 30/(15+x)=9/2
x^2=25 so x=5!!!whe 30/(15-x)is time fo upstream and 30/(15+x)is downstream ..and the sum eqls total time.. - 12 years agoHelpfull: Yes(6) No(11)
- Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
30 + 30 = 4 1
(15 + x) (15 - x) 2
900 = 9
225 - x2 2
9x2 = 225
x2 = 25
x = 5 km/hr. - 12 years agoHelpfull: Yes(5) No(14)
- then how did it come back?? :)
- 12 years agoHelpfull: Yes(4) No(0)
- speed of boat B is = (d+u) / 2
speed of stream S is= (d-u) / 2 where d for downstream and u for upstream
given that speed of boat =15km/h
and downstream d= 30 km/h
put the value 15= (30+u)/2
so we get u = 0 km/h
put the value in the stream formula s= (30-0)/2
speed of stream is = 15km /h ---> [answer].
we can prove it given time is 4hrs and 30 min= 9/2
t = d/s
d/15 + d/30 = 9/2 so distance =45 km
time required for for 45 km is
45/15 = 3 hrs
45/30 = 1.5 hrs
so 3 + 1.5 = 4.5 ( 4 hrs 30 min) -----/ proved - 8 years agoHelpfull: Yes(3) No(0)
- 5 km/hr.
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
Therefore,
30/(15+x) + 30/(15-x) = 4(1/2)
=> 900/(225-x^2) = 9/2
=> 9x^2 = 225
=> x^2 = 25
=> x = 5 - 11 years agoHelpfull: Yes(2) No(1)
- Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
30 + 30 = 4 1
(15 + x) (15 - x) 2
900 = 9
225 - x2 2
9x2 = 225
x2 = 25
x = 5 km/hr.
- 9 years agoHelpfull: Yes(2) No(0)
- The question might be wrong if it is 30km distance then the answer 5km/hr could be the answer
- 11 years agoHelpfull: Yes(1) No(0)
- if speed of stream is 15 kmph(i.e 30 -15 =15 kmph)then it relative velocity of boat with respect to stream will be zero("0"),so it will not come back .
- 11 years agoHelpfull: Yes(0) No(1)
- let speed of boat=a
speed of stream=b
now we have a=DOWNSTREAM+UPSTREAM/2
b=DOWNSTREAM-UPSTREAM/2
in question we have asked stream speed
threrefore b=DS-US/2=30-15/2=15/2=7.5
ans=7.5 - 8 years agoHelpfull: Yes(0) No(0)
- speed of the boat = 15 kmph
speed of the boat stiill in water means ( speed of the boat + speed of the stream ) = 30 kmph
therefore, speed of the stream = (speed of boat+ speed of stream ) - speed of boat
i.e..,, 30-15 = 15kmph.
- 8 years agoHelpfull: Yes(0) No(1)
- Explanation:
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr
So we know from question that it took 4(1/2)hrs to travel back to same point.
So,
3015+x−3015−x=412=>900225−x2=92=>9x2=225=>x=5km/hr
3015+x−3015−x=412=>900225−x2=92=>9x2=225=>x=5km/hr
- 8 years agoHelpfull: Yes(0) No(0)
Capgemini Other Question