Mark ate half of a pizza on Monday. He ate half of what was left on Tuesday and so on. He followed this pattern for one week. How much of the pizza would he have eaten during the week?

• For each successive day half of the quantity is eaten and half is left
  So for seven days total 1-(1/2^7)=1-(1/128)=127/128 quantity would have been eaten
• 12 years agoHelpfull: Yes(5) No(1)
• Mark ate half the pizza on Monday. On Tuesday, he would have
  ate half of the remaining pizza i.e. 1/4 of the original
  pizza. Similarly, he would have ate 1/8 of the original
  pizza on Wednesday and so on for the seven days.
  
  Total pizza Mark ate during the week is
  
  = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
  
  = 127/128
  
  = 99.22% of the original pizza
• 11 years agoHelpfull: Yes(2) No(0)
• pizza would he have eaten during the week = 1- (0.5)^7
  1/2 +1/4 +1/8 .. + 1/2^7
  
  sum of GP = a[1-r^n]/ (1-r) = (1/2)(1-0.5)^7)/(1/2)= (1-0.5)^7)
• 12 years agoHelpfull: Yes(1) No(2)
• pizza would he have eaten during the week = 1- (0.5)^7
  1/2 +1/4 +1/8 .. + 1/2^7
  
  sum of GP = a[1-r^n]/ (1-r) = (1/2)(1-(0.5)^7)/(1/2)= (1-(0.5)^7))
• 12 years agoHelpfull: Yes(1) No(0)
• he would have eaten 127 pizza out of 128 pizza during the week.
  sol:-
  Let Mark has 128 pizza at the starting of the week then he will eat on
  mon-64 pizza
  tue-32 pizza
  wed-16 pizza
  thu-8 pizza
  fri-4 pizza
  sat-2 pizza
  sun-1 pizza
  hence,total pizza eaten by Mark during a week=64+32+16+8+4+2+1=127 pizza ans.
• 12 years agoHelpfull: Yes(0) No(3)