the sum of three nos are 68.if first no and second no are in the ratio of 2:3 and second no and third no are in the ratio of 5:3.then find second number?

• 30 ans.
  sol:-
  Let x,y,z are the 1st,2nd,3rd numbers then a/c to the problem,
  x+y+z=68---(i)
  x/y=2/3 -> x=2y/3---(ii)
  y/z=5/3 -> z=3y/5---(iii)
  putting the value of x and z in equation (i) then we get:
  2y/3 + y + 3y/5=68
  34y=68*15
  y=30 ans.
• 12 years agoHelpfull: Yes(3) No(1)
• The ratio of first and second number is 2:3 = 2x:3x
  The ratio of second and Third number is 5:3 = 5x:3x
  The ratio of first ,second and third number is =10:15:9=10x:15x:9x
  The sum of the three numbers are 10x+15x+9x = 68
  34x = 68
  x = 2
  Then the three numbers are 20,30,18.
  then the second number is 30
• 12 years agoHelpfull: Yes(2) No(0)