In a two digit number it is known that its unit's digit exceeds its ten's digit by 4 and that the product of the given number and the sum of its digits is equal to 208, What is the number ?

• 26*8= 208
  
  number is 26.
  
  (2x+4)*(10x+x+4)= 209
  
  solving it, we get
  x= 2
• 12 years agoHelpfull: Yes(14) No(1)
• 208 = 4*52 = 13*16 = 8*26
  
  out of these only 26*8 satisfy the condition that unit's digit exceeds its ten's digit by 4 and that the product of the given number and the sum of its digits is equal to 208,
  
  so number is 26.
• 12 years agoHelpfull: Yes(10) No(2)
• xy is 2 digit no.
  y-x=4;
  (10x+y)*(2x+4)=208;
  sub y=x+4;
  we get 26 as ans.
  
• 11 years agoHelpfull: Yes(6) No(0)
• 26
  
  26*(2+6) => 26*8 = 208
• 12 years agoHelpfull: Yes(3) No(4)
• FACTORS OF 208,104,52,26,13 ...
  SO 26 * (2+6) = 208
• 11 years agoHelpfull: Yes(2) No(0)