L&T
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Numerical Ability
Permutation and Combination
.Six persons A,B,C,D,E & F went to solider cinema. There are six consecutive seats. A sits in
one of the seats
followed by B, followed by C and soon. If a taken one of the six seats , then B should sit
adjacent to A. C
should sit adjacent A or B. D should sit adjacent to A, B,or C and soon. How many
possibilities are there?
Read Solution (Total 6)
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- A and B should be adjacent , so A and B taken together. 2!
C should be adjacent to A or B. So (AB) and C taken together. 2!2!
D should be adjacent to A,B or C. SO ((AB)C) and D taken together. 2!2!2!
E should be adjacent to A,B,C or D. SO (((AB)C)D) and E taken together. 2!2!2!2!
F should be adjacent to A,B,C or D. SO ((((AB)C)D)E) and F taken together. 2!2!2!2!2! = 32 ways
- 11 years agoHelpfull: Yes(42) No(1)
- 1*2*2*2*2*2=32
- 11 years agoHelpfull: Yes(4) No(5)
- 7 possible ways ,
- 11 years agoHelpfull: Yes(1) No(17)
- 32 ways..
1+5(5c1)+10(5c2)+10+5+1=32 - 10 years agoHelpfull: Yes(1) No(0)
- A can sit in 6ways first.B can sit 2 ways if A sits in other than extreme ends,C has 2 ways and so on
Hence 6*2*2*2*2*1=196ways
If a sits in one of the extreme ends A can sit in 2 ways and the remaining persons can sit in 1 ways each hence 2 ways
so total 198 ways - 10 years agoHelpfull: Yes(0) No(4)
- He has gain = 15 - 12 = 3,
Gain% = (3/12) x 100 = (100/4) = 25.
He has 25% gain. - 4 years agoHelpfull: Yes(0) No(0)
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