A father’s age is 4 times the age of his elder son and 5 times the age of his younger son. When the elder son lived to three times his present age, then father’s age will exceed his younger son’s age by 32 yrs. What is the age of the father?

• suppose the fathers age=x
  age of elder son is=(1/4)x
  age of younger is =(1/5)x
  according to question
  the age difference btwn younger and father is 32
  so x-(1/5)x=32
  x=40years
  so father is 40 yrs old
• 11 years agoHelpfull: Yes(23) No(4)
• 40 years
  ages of sons are 8 and 10 years.
  Age difference between father and younger son will always be '32' years as at a time when the elder son lived to three times his present age,
• 11 years agoHelpfull: Yes(4) No(6)
• let age of elder and younger be L and Y.
  
  the present age conditions are F(fathers age) = 4L and F = 5Y.----(i)
  
  when elder lived three times i.e L = 3L which is L has grown 2L from present age.
  
  now Fathers age exceed younger by 32 ..can be written as
  
  F + 2L = (Y + 2L) + 32 , when elder grows 2L then father and younger as grow the same.
  
  from (i) L = F/4 and Y = F/5.
  
  substitute in the above equation making all into F terms .
  
  we get F=40 on solving
• 11 years agoHelpfull: Yes(2) No(5)