The original price of a car was RS.23600.Because the car owner thought he could get more money for the car,he increased the price of the car to 160% of its original price.After a week,the car had not sold,so the owner then discounted the price by 20%,the car was finally sold.What price was the car sold for?

• Car sold at Rs.30208.
  
  
  160% of Original Price, X = 23600*160/100 = 37760
  Discount 20% in X, Y = 37760*20/100 = 7552
  
  Finally Car sold at the price of = X - Y
  ==> 37760 - 7552
  ==> 30208
  
  Car sold at Rs.30208.
• 12 years agoHelpfull: Yes(24) No(7)
• Car sold at Rs. 49088
  
  Initially the price of car is 100%.
  car owner increase 160% of its original cost so. The cost is 260%.
  After giving 20% discount the cost is 208%.
  so 100 -----23600
  208-----x
  so x=49088
• 12 years agoHelpfull: Yes(9) No(19)
• The price was the car sold for Rs 30208.
  
  Original price of the car is 23600
  After increasing as 160% the price is 37760
  20% Discount on 37760 is 7552
  Finaly the price which the car sold for 37760-7552=30208
• 12 years agoHelpfull: Yes(6) No(3)
• car was rs.23600
  now at first price race to 160% which is=((23600*160)/100)....(1)
  now 20% discount so selling price is (100-20)%=80% of the price in sol (1)
  so the price car sold for=(23600*160*80)/(100*100)=30208
• 12 years agoHelpfull: Yes(3) No(1)
• original price of car=23600
  price of car with 160%=61360
  now final price of car with 20% dis.=61360-(61360*20/100)=49088
  so ans is 49088
  
  
• 12 years agoHelpfull: Yes(2) No(0)