the sum of three numbers is 136.if the ratio between first and second be 2:3 and that between second and third is 5:3,then the second number is?

• sum of 3 nos is 136(given)
  A:B=2:3--->(1) & B:C=5:3--->(2)(given)
  To obtain b's ratio from (1) and(2),
  B:C=(3/5)*5:(3/5)*3=3:9/5
  so,A:B:C=2:3:9/5=10:15:9(dividing each term by 5)
  Second number is=(136*(15/(10+15+9)))=60
  
  The second number is 60.
  
• 12 years agoHelpfull: Yes(5) No(1)
• Let the 3 nos. be x y z.
  
  x+y+z=136
  
  x/y = 2/3 => x = (2y/3)
  y/z = 5/3 => z = (3y/5)
  
  Substituting....
  
  y=60
• 12 years agoHelpfull: Yes(3) No(0)
• Since the ratio between 1st & 2nd nos. is 2:3 and that between 2nd & 3rd is 5:3. Then the nos. are in ratio 10:15:9.
  So, the 2nd no. is 15/34*136 = 60
• 12 years agoHelpfull: Yes(3) No(0)
• hai lalith its correct.but i have an doubt .how 3/5 will come in that simplification
• 12 years agoHelpfull: Yes(2) No(2)
• 
  Ans is 60
  first find the lcm of b's part in both the ratios.
  here it will be 15
  now convert the two ratios to 10:15 and 15:9h
  now the final ratio becomes 10:15:9
  hence the second no is=(15/(10+15+9))*136=60
  
• 12 years agoHelpfull: Yes(1) No(0)
• a:b:c
  2 3
  5 3
  there will be cross multiply
  2*5:3*5:3*3
  10:15:9
  so second number is
  15*136/34=60 ans
• 12 years agoHelpfull: Yes(1) No(0)