how many 4 digit number can be formed by 0,1,2,3,4,5, number is divisible by 4

• Last two digits can be 00,04,12,20,24,32,40,44,52 that is 9 possibilities for last two digits.For the hundredth place digit all 6 possibilities exist.For the thousand place we have 5 options (1,2,3,4,5 ). Hence the solution is 5*6*9=270
  
• 9 years agoHelpfull: Yes(33) No(14)
• without repeatation:
  case-1 when one of last two digit of them having 0 (04,20.40,)then no. of ways 4*3*3=36
  case-2 when one of last two digit of them not having 0 (12,24,32,52) then number of ways 3*3*4=36
  total no.of ways is 36+36=72 nos.
• 9 years agoHelpfull: Yes(30) No(3)
• without repetition:
  
  case-1:last 2-digit contains zero-04,20,40(3 ways)so the 100th and 1000th place can be filled up in 4*3 ways.So totla=4*3*3=36 ways
  case-2:when last 2-digit doesn't contain zero-12,24,32,52(4 ways) and the 1000th place can be filled up in 3 ways(as we can't place 0 there) and 100th place in 3 ways,So total=3*3*4=36
  So total numbers without repetion=36+36=72
  
  With repetition:
  
  00,04,12,20,24,32,40,44,52(9 ways),1000th place in 5 ways(as we can't use 0 ) and 100th place in 6 ways.So total =9*5*6=270
  
• 9 years agoHelpfull: Yes(14) No(0)
• total ans 144
• 9 years agoHelpfull: Yes(7) No(10)
• case-1 when iast two digit one of them having 0(04,20.40,)then no. of ways 4*3*3=36
  case-2 when last two digit is 12,32,52,24 then number of ways 4*3*4=48
  total no.of ways is 36+48=84
• 9 years agoHelpfull: Yes(7) No(5)
• 04,12,20,24,32,40,52 ...... 5*6*7
• 9 years agoHelpfull: Yes(4) No(3)
• case 1: 4*3*2*1 = 24 (when in unit place we put zero(0))
  case 2: 3*3*3*1 = 27 (when in unit place we put two(2))
  case 3: 4*3*1*1 = 12 (when in tens place we put zero(0))
  case 4: 3*3*1*1 = 9 (when in tens place we put two(2))
  
  so total possible number can be formed = 24+27+21 =72.
• 9 years agoHelpfull: Yes(3) No(3)
• To be divisible by 4 last 2 digit must be divisible by 4. So, the last two digit can be {(0,4), (2,0), (4, 0)} and {(1, 2), (2, 4), (3, 2), (5,2)}
  So, there are three ways where last two digit have 0 and there are 4 ways where last two digit are non-zero. The remaining 2 digits can be arranged in following way
  Total ways = 4*3*3 + 4*3*4 = 84
• 9 years agoHelpfull: Yes(3) No(1)
• 0,1,2,3,4,5 divisible by 4
  Ans:
  _ _ _ _
  last two digit should be divisible by 4 w/o repeat..
  so first write possibles zeros and other number
  Case:1
  04,20,40
  __ __ [__ __]
  last two places 3 ways remaining two places 4*3ways
  so totally 4*3*3=36;
  Case:
  except zero 12,24,32,52
  __ __ [__ __]
  last two digits in 4 ways and remaining 2 places are 4*3
  totally 4*3*4=48
  so Case1 and Case2
  36+48=84 ways
• 9 years agoHelpfull: Yes(2) No(1)
• the last two digits should be divisible by 4 in ordeer to complete divisibility of the number.
  so, the possibilties are 04, 20,40,12,24,32,52
  so total is (36+48) = 84
• 9 years agoHelpfull: Yes(2) No(0)
• 9*4+2*12=60
  Last two digit possible 24,12,32,52,20,40
  
• 9 years agoHelpfull: Yes(1) No(8)
• ans 225
  for thousand place we have 5 digits
  for hundred place 5 digit
  for last 2 places i.e ten and unit place
  00
  12
  04
  20
  24
  32
  40
  44
  52
  9 numbers which are divisible by 4
  so total no of ways=5*5*9=225
  
• 9 years agoHelpfull: Yes(1) No(4)
• The divisibility rule 0f 4 states that sum of last two digit has to be divisible by 4.
  so the combinations we get is:
  (4,0), (0,4), (1,3),(2,2),(3,1),(4,4),(6,2),(2,6),(5,3),(3,5),(7,1),(1,7),(8,8),(9,7),(7,9)
  
  As we have to find the four digits number.. so the digits can range from 1000 to 9999. So each of the above combinations will come 100 times from 1000 to 9999. eg: 1040,1140,1240............9940
  
  as here number of combinations are 15.. total numbers are 15*100= 1500
• 9 years agoHelpfull: Yes(1) No(1)
• with repetition
  case 1 : last two digit containg 0
  00,04,20,40(4 ways)
  5*6*4=120
  case 2: last two digit without 0
  12,24,32,44,52(5 ways)
  5*6*5=120
  answer:120+150=270.
  Without Repetition :
  case 1 : last two digits containg 0
  04,20,40(3 ways)
  4*3*3=36
  case 2: last two digits without 0
  12,24,32,52(4 ways)
  4*3*4=48
  answer:36+48=84..
• 9 years agoHelpfull: Yes(1) No(1)
• how@binesh
• 9 years agoHelpfull: Yes(0) No(0)
• Ans must be ->75
• 9 years agoHelpfull: Yes(0) No(3)
• Sorry my previous Ans ..
  it should be 63.
• 9 years agoHelpfull: Yes(0) No(3)
• answer will be 63
  4*3*2*1 when in unit place we put zero+
  3*3*3*1 when in unit place we put two+
  3*3*2*1when in unit place we put four=63
  
• 9 years agoHelpfull: Yes(0) No(0)
• 4 digit number can be formed as:-
  -First digit should not be zero.
  So, four digits number should be. 5*5*4*3=300
  And number should be divided by 4.
  So,300/4=75;75/4=18;18/4=4;4/4=1.
  Hence, answer should be. 75+18+4+1=98
• 9 years agoHelpfull: Yes(0) No(1)
• ans is 72 we can make 8 groups and each group will give u 9 numbers
  
  
  like 20
  
  5620
  3420
  
  
  3*3and lat 2 digit will be 20
• 9 years agoHelpfull: Yes(0) No(0)
• 36 explain
• 9 years agoHelpfull: Yes(0) No(0)
• without repetition answer should be 72 as i agree with siddharth prakash singh solution.
• 9 years agoHelpfull: Yes(0) No(0)
• last 2 digits can be 04,12,20,24,32,40,44,52 that is 8 ways
  100th palce in 6 ways
  1000s place in 5 ways
  8*6*5=240
• 9 years agoHelpfull: Yes(0) No(0)