Certain numbers of persons are able to finish a work in 25 days. If the number of persons are increased by 10, then they can finish the same work in 10 days less. How many persons were employed initially to do the work?

• 25x = 15*(x+10) =15x+150
  10x=150
  x=15
  
  so initially 15 persons were employed.
• 11 years agoHelpfull: Yes(7) No(0)
• x men in 25 days
  1 man in 25x days;
  
  x+10 men in 15 days
  1 man in 15(x+10)days
  so, 25x=15(x+10)
  so, x=15 men initially
• 11 years agoHelpfull: Yes(3) No(1)
• Suppose x persons were employed initially.So if they are taking 25 days to finish a work, in 1 day they will finish 1/25th part of a work.
  x--->in 1 day----> 1/25 th part
  x+10->in 1 day---> ? part. By cross multiplying,(x+10) people will complete(x+10)/25x th part of a work in 1 day, but it is mentioned that (x+10) people are taking (25-10)=15 days,so in 1 day they will complete (1/15) th part of a work so by equating the part of a work done by (x+10) people in 1 day: 1/15 = (x+10)/25x we get,1/3=(x+10)/5x, now cross multiply, 5x=3(x+10) => 5x=3x+30 => x=15 people were employed initially.
• 11 years agoHelpfull: Yes(1) No(0)