Cadbury manufactures a chocolate box which contains “x” number of chocolates. There are three
houses A, B and C in the neighbourhood of Cadbury. Since it is a new variety of chocolate, themarketing manager of Cadbury decided to distribute free chocolates to the children in theneighbouring houses A, B and C. In House A there are 3 children, in B there are 5 children, and in Cthere are 7 children. After distributing the chocolates, he was left with one chocolate in each case. Howmany chocolates did he have in the beginning for distribution?(a) 204 (b) 211 (c) 214 (d) 217

• Here total no. of children = 15
  So the No. of chocolates must be a number which when divided by 15 gets 1 reminder
  so 211 is answer
• 12 years agoHelpfull: Yes(27) No(0)
• 211
  
  LCM of 3,5,7 is 105.
  Number of choclates can be
  105*1+1=106
  or
  105*2+1=211
  or
  ....
  ..
  
  so from given options 211 is correct one.
• 12 years agoHelpfull: Yes(13) No(1)
• 211
  lcm = 105
  now the number must be multiple of 105 and then after adding 1 to them we can get it easily
  105*1+1=106
  105*2+1=211
  and now 211 is the answer matching with our options
• 12 years agoHelpfull: Yes(3) No(2)