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Arvind, a mason, decided to build a small house. For constructing the house he had to mix gravel, sandand cement in the ratio 7:5:3. The cement costs Rs.250 a bag which contains 10 kg of cement. He hasspent Rs.4500 to buy cement. How much will he have to spend for sand which costs Rs.70 for a 20 kgbag?(a) Rs.1050 (b) Rs.2050 (c) Rs.1075 (d) Rs.2000
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- cost of cement=Rs 4500
so wt. of cement required to construct house= (4500/250)*10= 180 Kg
now, total wt of material can be evaluate from following equation:
3x/15=180 kg
so,
x=900kg
hence total material req.=900kg
wt of sand used= 5/15 * 900= 300kg
cost of sand=70/20 * 300 =Rs 1050 - 12 years agoHelpfull: Yes(24) No(0)
- 4500/250=18 bags of cement=180 kg of cement,
cement : sand=3:5,
(180/3)=((20kgs*x bags)/5),
x=15bags=15*70=1050/- - 12 years agoHelpfull: Yes(5) No(3)
- 1050 is correct.
For 10*4500/250 = 180 kg cement, you need 300 kg sand.
@ Rs 70 for 20 kg back, amt to be spent on sand = 70*300/20 = 1050. - 12 years agoHelpfull: Yes(4) No(2)
- cement= 4500rs=180kg
total material=840kg
sand=300kg=1050rs
that means 1050 is correct - 12 years agoHelpfull: Yes(4) No(3)
- 4500/250=18
3/15*x=180
x=5*180
5/15*5*180=5*60=300
300/20=15
15*70=1050 - 12 years agoHelpfull: Yes(1) No(0)
- ans given is (b) but my ans is (a) i.e. Rs.1050
- 12 years agoHelpfull: Yes(0) No(2)
- @garima please explain the logic behind the sum"How many 3-digit numbers have even number of factors?"...i have asked earlier
- 12 years agoHelpfull: Yes(0) No(0)
- @garima can u explain where the 300kg came from?
- 12 years agoHelpfull: Yes(0) No(0)
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