If [K+2]/[K+3] = K/9
then which of the following operations between the values of K will give an integer as answer.

• solving the equation we get:
  k^2 - 6k -18 =0
  solving the value of k
  we get k= (6+ undr root of 108)/12 and (6- undr root of 108)/12
  multiplying these 2 roots..
  we get:
  -72/12= -6
• 11 years agoHelpfull: Yes(6) No(1)
• Simplifying the equation we get:
  k^2 - 6k -18 =0
  
  here sum of roots = -(-6)/1 =6... integer
  Product of roots = -18/1=-18.. integer
  
  so sum and multiplication of roots will give integer result.
• 11 years agoHelpfull: Yes(6) No(1)
• Here k = 3+- 3Root 3
  
  So when u add two value of k, u get 6 as answer which is integer.
  When u multiply 2 values of k,
  u get -18 as answer. which is an integer.
  (3+3root3)*(3-3root3)= 9-27 = -18
  
  so multiplication or addition will give integer answer.
• 11 years agoHelpfull: Yes(3) No(3)
• This question is for Today's puzzle.
  
  Pls do not post answers here.
• 11 years agoHelpfull: Yes(3) No(0)