friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order IN 7 rounds. A;B;C;AB;BC;AC;ABC. Final round measure is 155 kg then find the average weight of all the 7 rounds?

• let d age of A,B,C are x,y,z respectively.
  given, x+y+z=155,
  after 7th round the total age be x+y+z+(x+y)+(y+z)+(x+z)+(x+y+z)=4(x+y+z)
  hence avg weight (4*155)/7=88.57
• 11 years agoHelpfull: Yes(28) No(1)
• ans is 88.57
  given last rnd is 155=A+B+C,
  1st 3 rnd A+B+C=155
  next AB+BC+CA=155*2
  adding all And diveded by 7 we get 88.57
  
• 11 years agoHelpfull: Yes(10) No(2)
• Average Weight = A+B+C+AB+BC+CA+ABC/7
  so we known that :
  
  A+B+C+AB+BC+CA+ABC/7 = average and ABC= 155,
  = A+B+C+AB+BC+CA+155/7= Average,
  = 4(ABC)/7 = average,
  average= 88.57
• 11 years agoHelpfull: Yes(3) No(1)
• abc=155
  a+b+c+ab+bc+ca+abc7=?
  4(abc)/7= 4*155/7=88.57
• 11 years agoHelpfull: Yes(2) No(0)
• The avg weight of A,B,C is 51.66kg
  so the avg value of all 7 rounds is
  A+B+C+AB+BC+AC+ABC
  51.66+51.66+51.66+(51.66*2)+(51.66*2)+(51.66*2)+155
  =88.56KG (ANSWER)
  
• 11 years agoHelpfull: Yes(2) No(0)