1 2 3 50

S = 3. something...3 x 10^64
12 years agoHelpfull: Yes(2) No(3)
multiply numerator and denominator by n(n+1)/2=50*51/2=25*51
thus u'll get (1*1!+2*2!+3*3!+4*4!+....+49*49!+50*50!)/(25*51)
=((2-1)*1!+(3-1)*2!+(4-1)*3!+.....+(51-1)*50!)/(25*51)
=(2!-1!+3!-2!+4!-3!+...+51!-50!)/(25*51)
=(51!-1!)/25*51
=2*49!-1/(25*51) [ans]
=> explanation
25*51=1275
so we take sum of 1275 like as
(1+2+3+..........+49)
and then multiply by each and we get
(1*1!+2*2!+3*3!+4*4!+....+49*49!+50*50!)
the answer of this ques after cal can be
3.04*10^64(ans)
12 years agoHelpfull: Yes(2) No(9)
ans is 3.1035*10^64
12 years agoHelpfull: Yes(2) No(1)
If the option is given my trick help to select option
its last digit is 3
because after the 5! last digit is zero so we add 1!+2!+3!+4! = 1+2+6+24 => 33
so the sum of 1!+2!+3!+.....50! gives last digit 3
12 years agoHelpfull: Yes(2) No(1)
giv me some proper solution for the problem
12 years agoHelpfull: Yes(0) No(0)

1!+2!+3!+..........50!