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total possible 5 digit numbers from digits 0 to 9(repetition allowed) that are divisible by 4??
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- Last 2 digits can be 00,04,08,12,16,20,......96 .. total 25 combinations.
For First place , u have 9 possible digits from 1-9.
For next two places, you have 10 possible digits from 0-9.
so total possible 5 digit numbers from digits 0 to 9(repetition allowed) that are divisible by 4 = 9*10*10*25= 22500 - 12 years agoHelpfull: Yes(23) No(2)
- 9*10*10*25=22500
- 12 years agoHelpfull: Yes(1) No(0)
- 9 * 9 * 9 * 15
- 12 years agoHelpfull: Yes(0) No(9)
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