Consider the events "it is night" and "it rains" are mutually exclusive events. Find the probability that it rains and it is night if P(it rains)=0.1 and P(it is night)=0.5.

• let a=it is night
  b=it rains
  a and b are mutually exclusive event so p(ab)=0
  hence probability of it rains and it is night =0
• 9 years agoHelpfull: Yes(12) No(4)
• ans-0.05
  as both are mutually exclusive events,the resultant probability is product of their probabilities
  P((it rains) and (it is night))=0.1 *0.5=0.05.
• 9 years agoHelpfull: Yes(6) No(6)
• P(AUB)=P(A)+P(B)=0.6
• 9 years agoHelpfull: Yes(2) No(7)
• given the both events are mutually exclusive evensts. the we should multiply both th events .
  p(A)*p(B)= 0.05
• 8 years agoHelpfull: Yes(2) No(2)
• Two events are mutually exclusive if they cannot occur at the same time.
  
  So the required probability =0
• 8 years agoHelpfull: Yes(2) No(1)
• P(AUB) = P(A)+P(B) = 0.1+0.5 =0.6
• 9 years agoHelpfull: Yes(0) No(8)
• given mutually exclusive ...hence p(ab)=0 and also p(aub)=p(a)+p(b)-p(ab)=0.6
• 8 years agoHelpfull: Yes(0) No(1)