There are 4 gold chain. 1 has 5links, other has 4 links and the other 2 have 3 links.
goldsmith takes 50 paise to open the link and 1.00/- to attach the link. what is least cost to
bake whole bracelet.

• Let,the shape of the bracelet is closed circle.[It is supposed to assume]
  gold chain with 5 links: A_ _ _ _ _B
  gold chain with 4 links: C_ _ _ _D
  gold chain with 3 links: E_ _ _F
  gold chain with 3 links: G_ _ _H
  
  We,generally hold a common notion that since there are 4 gold chains and since we are to make a closed circular shaped bracelet, so,we have to join the ends namely :(B,C),(D,E),(F,G),(H,A),i.e, total 4 links have to be broken and further joined,i.e, total cost will then be 4(1+.50)= 6 rupees.
  
  But,now we will tackle the problem in a different way.
  Let, all the 3 links of GH chain are broken.
  Then,
  with the help of 1st broken link, B and C ends are joined.
  with the help of 2nd broken link, D and E ends are joined.
  and,
  With the help of the remaining broken link, F and A ends are joined.
  So, the above mentioned method explains us that breaking only 3 links and subsequently joining two free ends with each link facilitates us to make a whole closed circular shaped bracelet.
  Therefore,the cost in this case : 3*(1+.50) = 3*(1.50)=4.50 rupees;
  
  So,evidently,the least cost to make the whole bracelet :4.50 rupees .
  
  Thank to all..:-):-)..
• 11 years agoHelpfull: Yes(53) No(6)
• simply we can say there are 4 gaps to form a circle(reason is chain is in circle shape only) in b/w chain and one link should be open to connect and reconnectthe chain so 4*1.00+1*50p= rs 4.50
• 10 years agoHelpfull: Yes(2) No(2)
• IT IS RIGHT THAT WE JUST HAVE TO OPEN 3 LINK CHAIN AND THEN EACH LINK SHOULD JOINT ANOTHER LINK THEN WHOLE BUDGET GOES TO 4.5 RUPEES..BUT FOR THE WHOLE CIRCLE OF BRACELET WE SHOULD JOIN THE REMAINING LINK SO FOR THE REMAINING LINK 1 RUPEES. SO WHOLE BUDGET IS 4.5+1=5.5 RUPEES
• 8 years agoHelpfull: Yes(0) No(3)
• cracking my brain i got ans is 5.50rs
• 7 years agoHelpfull: Yes(0) No(1)