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Probability
Three faces of a fair die are Yellow, two faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is
A)1/36 B)1/18 C)1/32 D)1/37 E)None of these
Read Solution (Total 6)
-
- Probability of getting yellow color = P(Y) = 3/6 = 1/2
Probability of getting red color = P(R) = 2/6 = 1/3
Probability of getting blue color = P(B) = 1/6
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/2 x 1/3 x 1/6 = 1/36(ans) - 12 years agoHelpfull: Yes(37) No(6)
- Since, the die is tossed thrice ,so total number of possible outcomes : 6^3 = 216.
Now,
In the 1st toss,we can get a yellow face in 3 ways.
For each of these 3 ways,
In the 2nd toss,we can get a red face in 2 ways.
So, we can get yellow in the 1st and red in the 2nd tosses in 3*2=6 ways.
And for each of these 6 ways,
In the 3rd toss,we can get a blue face in 1 way.
So, total no. of favourable cases w.r.t our desired event = 3*2*1=6.
So, by the classical definition of the probability ,
the required probability = (6/216)= (1/36)
So, the correct Option is : A)(1/36) - 12 years agoHelpfull: Yes(19) No(4)
- given that 3 yellow faces,2 blue faces
dice are thrown 3 times
prob=(3c1*2c1*1c1)/(6*6*6)
ans:1/36 - 12 years agoHelpfull: Yes(5) No(1)
- Probability of getting yellow color = P(Y) = 3/6 = 1/2
Probability of getting red color = P(R) = 2/6 = 1/3
Probability of getting blue color = P(B) = 1/6
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/2 x 1/3 x 1/6 = 1/36 - 11 years agoHelpfull: Yes(2) No(0)
Probability of getting yellow color = P(Y) = 3/6 = 1/2
Probability of getting red color = P(R) = 2/6 = 1/3
Probability of getting blue color = P(B) = 1/6
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/2 x 1/3 x 1/6 = 1/32(ans)
- 12 years agoHelpfull: Yes(1) No(17)
- die is tossed 3 times p(n)=216
=3x2x1/216
=1/36 - 7 years agoHelpfull: Yes(0) No(0)
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