At the foot of a mountain the elevation of its summit is 45 degrees. After ascending one
KM towards the mountain upon an incline of 30 degrees, the elevation changes to 60
degrees. Find the Height of the mountain?

A)1.333Km
B)1.366Km
C)1.233Km
D)1.266Km
E)None of these

• At the foot of a mountain the elevation of its summit is 45 degrees. After ascending one KM towards the mountain upon an incline of 30 degrees, the elevation changes to 60 degrees. The Height of the mountain is guven by
  [ Height -- sin 30 ] = [ Height -- cos 30 ] tan 60
  whence Height = [tan 60 cos 30 -- sin 30 ] / [ tan 60 -- 1 ] km = 1.366 km
• 12 years agoHelpfull: Yes(14) No(17)
• @ Riya, please elaborate.
• 12 years agoHelpfull: Yes(13) No(0)
• http://www.topperlearning.com/forums/ask-experts-19/at-the-foot-of-a-mountain-the-elevation-of-its-summit-is-45-mathematics-some-applications-of-trigonometry-71870/reply
  
• 8 years agoHelpfull: Yes(2) No(0)
• Height of the mountain = sin60+sin30
  =1.366km
• 10 years agoHelpfull: Yes(1) No(0)
• http://tinypic.com/r/289zvj6/8
  Well as per the image, BE = FC = 1 sin 30
  AE = BD = 1 . hence DF = 1 sin 60
  CD = FC + DF = (1+√3)/2 = 1.366
• 10 years agoHelpfull: Yes(0) No(1)
• In the figure, AB represents the mountain of height h, say. In OCE,
  
  sin 30° =
  
  
  
  cos 30° =
  
  
  
  OE =
  
  In AOB,
  
  tan 45o =
  
  OA = AB
  
  CD = EA = OA - OE = h -
  
  BD = AB - AD = AB - CE = h - 500
  
  In BCD,
  
  tan 60o =
  
  
  
  Thus, the height of the mountain is 1.366 km.
• 6 years agoHelpfull: Yes(0) No(0)