The average of a couple was 23Yrs when they were married 5Yrs ago.The avg age of
the couple and a child, who was born during the interval, is 20Yrs now. How old is the
child now ?

A)2 Yrs
B)4 Yrs
C)3 Yrs
D)1 Yrs
E)None of these

• (a+b-5-5)/2=23;
  a+b=56;
  a+b+c/3=20;
  solving both c=4;
  B is the answer
• 12 years agoHelpfull: Yes(44) No(2)
• Age og child : B)4 yrs
  
  let d ages of the couple be 'a' and 'b'
  -> since the avg was 23 5 years ago.. the avg currently would be 28 yrs..
  -> hence, (a+b)/2=28... a+b=56
  the avg of couple n child's age is 20
  let age of child be 'c'
  hence, a+b+c=20*3=60...
  thus, age of child is 4yrs
• 12 years agoHelpfull: Yes(24) No(4)
• ans is b 4ys
  sol- let couple be x & y;
  a/q- before 5 yrs=
  x-5+y-5=23*2;
  x+y=56;
  again, let z be child,
  so, x+y+z=20*3;
  so, z=4yrs.
  
• 12 years agoHelpfull: Yes(9) No(0)
• average of couple 5 yr ago =23;
  average of today =23+5=28;
  average of child and couple today= (2*28+child)/3=20;
  so child =60-56=4 yr
• 10 years agoHelpfull: Yes(7) No(0)
• ANSWER: B [4 yrs]
  SOLUTION:
  Say, Cm,Cf,c are representing current ages of Couple-male, Couple-female and Child.
  Avg. of couple [2 people], 5 yrs ago= 23 yrs.
  So, (Cm-5)+(Cf-5)=2*23=46 => Cm+Cf=56
  Avg. of couple+child [3 people], now=20yrs.
  So, (Cm+Cf+c)=3*20=60
  We've already found the value of (Cm+Cf) i.e., 56.
  Therefore, c=60-56=4 yrs [Child's current age=4yrs]
• 12 years agoHelpfull: Yes(2) No(0)
• (x-5)+(y-5)/2=23=>x+y-10/2=23=>x+y=56
  x+y+c/3=20=>56+c/3=20=>56+c=60=>c=4yrs
• 11 years agoHelpfull: Yes(1) No(2)
• total age of couple before 5 year is 23*2=46.than after 5 year the sum of their age is 46+10=56.than at present sum of their age is 20*3=60..so child age is 60-56=4 year..
  
• 10 years agoHelpfull: Yes(1) No(0)
• Ans B) 4yrs
• 9 years agoHelpfull: Yes(1) No(0)
• Ans: 4yrs.
  
  
• 12 years agoHelpfull: Yes(0) No(4)
• none of these
  
• 11 years agoHelpfull: Yes(0) No(6)
• 5 yrs ago...(H-5)+(w-5)/2=23..from this h+w=56
  h+w+c/3=20....
  h+w+c=60....then c=4
• 10 years agoHelpfull: Yes(0) No(0)
• 4 let x be the age of couple added together at present,then (x-10)/2=23,
  therefore x=56. let the age of child be y,then (56+y)/3=20,so y=4.
  age of child=4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• before 5 yrs;
  age of couple=(23*2)=46 yrs
  after 5 yrs;
  age of couple=46+5=51 yrs
  now,
  age of couple & child=60 yrs
  so,age of child=60-(51+5)=4 yrs
  
• 10 years agoHelpfull: Yes(0) No(0)
• let d ages of the couple be 'a' and 'b'
  -> since the avg was 23 5 years ago.. the avg currently would be 28 yrs..
  -> hence, (a+b)/2=28... a+b=56
  the avg of couple n child's age is 20
  let age of child be 'c'
  hence, a+b+c=20*3=60...
  thus, age of child is 4yrs
  
• 10 years agoHelpfull: Yes(0) No(0)
• 4 yrs. (b) {(x+y)/2}-5=23..so,,x+y=56..so y=56-x
  {x+(56-x)+c}/3=20..so.c=4
• 10 years agoHelpfull: Yes(0) No(0)
• (a+b)/2=28;
  (a+b+c)/3=20;
  c=4
• 10 years agoHelpfull: Yes(0) No(0)
• x,y=couple's present ages
  5 yrs ago:(x-5)+(y-5)=23*2=46
  presently:x+y+z=20*3=60
  so z =60-56=4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• E 23+5=28 avg. Present age of couple.
  Let, x be d age of child
  So 28+x/2=20
  X=12
• 10 years agoHelpfull: Yes(0) No(1)
• let avg age of the couple five yrs ago be (a+b)/2-5=23
  and avg age including their child be (a+b+c)/3=20
  solving both we get c=4
  so b is the ans
• 10 years agoHelpfull: Yes(0) No(0)
• (20*3)-{2*(23+5)}=4 years..
  Ans = B
  
• 10 years agoHelpfull: Yes(0) No(0)
• If we assume x and y as ages of couple,
  we have x+y-10/2=23
  so we have x+y=56
  given average of couple and child as 20yrs
  let child age be z years
  then,x+y+z/3=20
  as we know value of x+y,substitute this 56 value in above equation
  56+z/3=20
  so z=4yrs,which is the age of child.
  answer is 4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• let husband =X yrs
  wife =y yrs
  child= z yrs
  avg 5 yrs ealier (x-5)+(y-5)/2=23
  on solving, x+y=56
  avg nw x+y+z/3=20
  56+z=60
  child age z=4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• Total age of the couple before 5 years=23*2=46
  Let now the child is x years,
  Now the total of three=46+10+x=56+x
  so 56+x=20*3 x=4
• 10 years agoHelpfull: Yes(0) No(0)
• B)
  c-10/2=23
  c=56
  c+child/3=20
  child=4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• (56+x)/3=20;
  x=60-56=4yr
• 10 years agoHelpfull: Yes(0) No(0)
• answer is b)4yrs
• 10 years agoHelpfull: Yes(0) No(0)
• before 5 yrs avg age was 23 yrs. so present age will be 23 + 5 = 28; but given that the avg of three is 20 but the age of couple 28+28. thus 28-20= 8. and for couple it will be 8+8 = 16.
  so we can found the age of child is 20-16 = 4 yrs
  
• 10 years agoHelpfull: Yes(0) No(0)
• x+y/2=23+5
  =51
  now child age and couple average age is x+y+z/3=20
  =60
  we know that x+y=51 then
  x+y+z=60
  51+z=60
  =60-51
  =9
  then present age of children is=9-5=4
• 10 years agoHelpfull: Yes(0) No(0)
• ans :-4
  a+b=56
  a+b+c=60
  c=4
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 4 years
  
• 9 years agoHelpfull: Yes(0) No(0)
• (M-5+w-5)/2=23-->M+W-10=46-->M+W=56
  (M+W+C)/3=20
  56+c=60
  C=4y
• 8 years agoHelpfull: Yes(0) No(0)
• Their present average,after 5 years
  (M+W)/2=28,
  M+W=56.
  After birth of child (M+W+C)/3=20
  M+W+C=60
  
  Child's age is 60-56=4years
• 8 years agoHelpfull: Yes(0) No(0)
• H+W=23+23
  after 5 years H+W=56
  given H+W+C=20+20+20
  H+W+C=60
  56+c=60
  c=4 yrs
• 4 years agoHelpfull: Yes(0) No(0)