8+88+888+.....+8888........8888. There are 21 “8” digits in the last term of the series.
Find the last three digits of the sum.

• 21*8=168 carry 16
  20*8=160+16=176 carry 17
  19*8=152+17=169
  the value is 968
  
  
  
• 9 years agoHelpfull: Yes(80) No(13)
• when we write this in sumation form...then.....
  At ones place 8 comes 21 times ....so...8*21=168
  At tens place 8 comes 20 times......so...8*20=160...but in this 16 is added, came from ones addition..so after adding 176 comes
  At hundred place 8 comes 19 times....so...8*19=152..after adding 17 from previous.....169 comes....so last three digit is.........968
• 9 years agoHelpfull: Yes(22) No(4)
• 8(1+11+111+1111+....)=8(............2121)=.......968
• 9 years agoHelpfull: Yes(20) No(5)
• 19th term->....88
  20th term-> ...888
  21th term->....8888
  adding last three digits of every term we get answer:568.
  
• 9 years agoHelpfull: Yes(13) No(6)
• Since. 8+88+888+8888+88888+888888+.........+"8" 19 times +"8" 20 times+"8" 21 times= 8[123456.......192021]
  Hence last three digit=8(.....19+20+21)= .... 968
• 9 years agoHelpfull: Yes(7) No(3)
• 21*8= 168 carry 16
  20*8=160+16(add previous carry)=176 now carry 17
  19*8=152+17=169
  Thus last 3 digit are 968
• 9 years agoHelpfull: Yes(6) No(2)
• @ gopinath for 21*8=168 carry 16 = 168
  20*8=160+16=176 carry 17= 176
  19*8=152+17=169 = 169
  take last units digit , 968
• 9 years agoHelpfull: Yes(4) No(1)
• 968
  21*8=16 8, 8
  20*8+16=17 6 6
  19*8+17=16 9 9
  so answer is 968
• 9 years agoHelpfull: Yes(3) No(2)
• 888*19=16872
  16872+88+8= 16968
  so last three digits will be 968
• 9 years agoHelpfull: Yes(3) No(0)
• 568 is the correct answer....968 is not even in the options
• 9 years agoHelpfull: Yes(3) No(0)
• can anyone plz tel me how wil we get 968
• 9 years agoHelpfull: Yes(2) No(0)
• 1
  11
  111
  1111
  -------------------
  121
  --------------------
  121*8=968
• 9 years agoHelpfull: Yes(1) No(2)
• (2)
  19th...............8 8 8
  20th...............8 8 8 8
  21st................8 8 8 8 8
  --------------------------------------------
  5 6 8
  --------------------------------------------
  
• 8 years agoHelpfull: Yes(1) No(0)
• please can any one explain
• 9 years agoHelpfull: Yes(0) No(0)
• can anyone explain this clearly..how the carry comes??
  
• 9 years agoHelpfull: Yes(0) No(0)
• 8+88+888......=8/9((10(10^n-1)/9)-n)
  as n=21
  by solving we get 9.87654321*10^20
  hence sum of last three digits is 0+0+0=0
• 9 years agoHelpfull: Yes(0) No(8)
• But how did 968 come??
• 9 years agoHelpfull: Yes(0) No(0)
• how carry comes?????eny 1 explain plz
• 9 years agoHelpfull: Yes(0) No(1)
• Can any1 explain this sum ???
  
• 9 years agoHelpfull: Yes(0) No(0)
• please show how 968 is coming...please show the calculations even.....
  nt getting clear.
• 9 years agoHelpfull: Yes(0) No(0)
• pls explain in an easy way how u got that last 968 ????
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 968
  
• 9 years agoHelpfull: Yes(0) No(0)
• 8+88+888+888888+888.....8888
  becouse every 8 is becouse it is multiplied by last two and added by last two
• 9 years agoHelpfull: Yes(0) No(1)
• 8*(19+20+21)=480
• 5 years agoHelpfull: Yes(0) No(1)