the number 272738 and 232342, when divided by n a two digits

• incomplete question !
• 9 years agoHelpfull: Yes(4) No(4)
• The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
  a. 7
  b. 8
  c. 5
  d. 4
  Explanation:
  From the given information, (272738 - 13, 232342 - 17) are exactly divisible by that two digit number.
  We have to find the HCF of the given numbers 272725, 232325.
  HCF = 25.
  So sum of the digits = 7.
• 7 years agoHelpfull: Yes(4) No(0)
• no..i think we hav to find the sum of the numbers 272738 232342 when divided by 2 digit no..
• 9 years agoHelpfull: Yes(0) No(4)
• answer is 2
  i had done in h.c.m method
  dividing greater no with small no and last no i got is 2
• 9 years agoHelpfull: Yes(0) No(3)
• as remainder is 13 & 17 so dividend must be greater than 17
  
  272738 = n*a+13 => 272725=n*a ---(1)
  232342 = n*b+17 => 232325=n*b ---(2)
  
  last two digit of (1)&(2) is 25 so n must be 25, no other two digit no. greater than 25 satisfies this
  
  272725=25*10909
  232325=25*9293
  
  n=25, sum of digits of n = 2+5 = 7
• 7 years agoHelpfull: Yes(0) No(0)