a volume of A are having in a container of sphere. how many semi hemispheres of B volume each will be required to transfer all the A in to semi hemispheres?

• ans is A/B. volume of sphere is A=(4/3)*pi*a^3 a is radius of sphere.volume of hemisphere is B=(2/3)*pi*b^3.A=x*B..x=A/B.x is the number of hemispheres of volume B that can sufficiently accommodate volume A.
• 12 years agoHelpfull: Yes(7) No(0)
• YES.. ANSWER IS A/B :) M SUREEE
  
• 12 years agoHelpfull: Yes(4) No(0)
• Listen guys and girls here nt given abt radius of both so we need to take same ...
  also given that semi hemisphere nt only hemisphere so hemisphere volume is 1/2(2/3*pi*r3).... and sphere volume is (4/3*pi*r3)...
  so if we taking the ratio of sphere to hemisphere it is 4....
• 12 years agoHelpfull: Yes(4) No(2)
• ANS IS a/b
• 12 years agoHelpfull: Yes(2) No(0)
• It's simple just recollect the volume formula's of both
  Sphere-4/3*pi*r^3
  hemisphere =2/3*pi*r^3 now S=KH i.e k=Sphere/Hemisphere
• 12 years agoHelpfull: Yes(2) No(0)
• pls tel e if the sol i hav given s ryt or not
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• I guess its A=nB.
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• A = 4/3 pi*r^3
  B = 1/2 * 2/3 * pi * r^3 (semi hemisphere)
  A/B = 4 = Ans
• 12 years agoHelpfull: Yes(0) No(3)