Q- 31x+ 32 y+ 34z= 0 , find x+y+z?

• 30x+x+30y+2y+30z+4z=0
  30(x+y+z)+x+2y+4z=0
  x+y+z= - (x+2y+4z/30)
• 11 years agoHelpfull: Yes(21) No(5)
• answer is -(y+3z)/31...
  
  31x+32y+34z = 0
  =>31x+(31y+y)+(31z+3z) = 0
  =>31(x+y+z)+y+3z = 0
  =>31(x+y+z) = -(y+3z)
  =>x+y+z = -(y+3z)/31....
• 11 years agoHelpfull: Yes(7) No(8)
• 32x-x+32y+32z+2z=0
  now taking 32 as a common multiple we get
  x-(x/32)+y+z+(z/16)=0
  or
  x+y+z=(x-2z)/32
• 11 years agoHelpfull: Yes(0) No(5)