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cost of 3 mango,4 pears cost 55 and cost of 1 apple, 5 pears cost 70 ,and cost of 2 mango, 5 apple cost 60...what the total cost of 1 app,1 mango and 1 pea?
Read Solution (Total 3)
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- answer is 35
3 mango,4 pear 3x+4y=55
5 pear ,1 apple 5y+z=70
5 apple, 2 mango 2x+5z=60
add all 5x+9y+6z=185 equation 1
equation 2 is 3x+4y = 55
by using z=70-5y put in to equation 2 and we get 5x-26y=-235 equation 3
subtract eq.2 - eq 3
we get y=10 , z= 20, x= 5
so x+y+z=35
- 12 years agoHelpfull: Yes(14) No(4)
- ==>3m+4p=55----->eq1
==>a+5p=70------->eq2
==>2m+5a=60------->eq3
now,add 1+2 eq===>a+3m+9p=125--->eq4
add 2+3 eq====>a+2m+10p=130--->eq5
solve 4 and 5 we get p=10,m=5 and a=20 so total cost is::::35
- 12 years agoHelpfull: Yes(3) No(6)
- by solving all 3 equations my ans=rs 25
- 12 years agoHelpfull: Yes(0) No(6)
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