The milk and water in two vessels A and B are in the ratio 4 : 3 and 2: 3 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C containing half milk and half water?

• milk in A=4/7 water in A=3/7 let x quantity of mixture from A be added to C
  milk in B=2/5 water in B=3/5 let y quantity of mixture from B be added to C
  hence,milk added from a + milk from b= 4x/7+2y/5
  water added from a + water from b= 3x/7+3y/5
  these two shud be equal as ratio in c is same for milk nd water
  therefore,(4x/7+2y/5)/(3x/7+3y/5)=1
  on solving,x/7=y/5
  or x:y=7:5
  
• 12 years agoHelpfull: Yes(57) No(0)
• let c.p. of 1liter milk is 1RS.
  now milk in 1st mixer is 4/7 and in 2nd mixure is 2/5.
  milk in finle mixer is 1/2
  now from mixure formula..
  4/7 2/5
  1/2
  1/10 1/14
  so ratio is 14/10 =7/5
  
• 12 years agoHelpfull: Yes(32) No(13)
• 4l milk + 3l water in first vessel
  2l milk + 3l water in second vessel
  
  add both mixture in third vessel at 1:1 ratio ,the mixture contains 6l milk : 6l water i.e half water and half milk
  
• 12 years agoHelpfull: Yes(19) No(16)
• Let the C.P of milk be Re 1 per liter. Milk in 1 liter mixture of A = 4/7 liter. Milk in 1 liter mixture of B = 2/5 liter. Milk in 1 liter mixture of C = 1/2 liter. C.P of 1 liter mixture in A=Re 4/7 C.P of 1 liter mixture in B=Re 2/5. Mean Price = Re 1/2. By rule of allegation we have:
  Mean Price ½ 1/10 1/14 Required ratio = 1/10 : 1/14 = 7:5.
• 12 years agoHelpfull: Yes(12) No(13)
• i think the ratio is 1:1
  milk and water ratio in vessel A is 4/3 and in B is 2/3
  and we want 1/1 in vessel c
  so the ratio vessel A and vessel B's liquid in c is 1:1
• 12 years agoHelpfull: Yes(7) No(16)
• ans. is 7:5
  Milk in 1 lit. mixture of A=4/7 lit.
  Milk in 1 lit. mixture of B=2/5 lit.
  Milk in 1 lit. mixture of C=1/2 lit.
  By rule of alligation we have required ratio X:Y
  Mean ratio= 1/2
  X=1/2-2/5=1/10
  Y=4/7-1/2=1/14
  X:Y= 14:10= 7:5
• 12 years agoHelpfull: Yes(6) No(2)
• the answer will be 7:5
  because the taotal amount of liquid in vessel A is 7L and in vessel B is 5L, so they have to be mixed in 7:5 ratio in order to obtain the half milk and half water in Vessel C, assuming 4:3 to be 4L and 3L resp.
• 12 years agoHelpfull: Yes(5) No(7)
• Ans. Ratio of A:B in vessel C should be 1:1
  
  Suppose A contains 4L Milk & 3L water & B 2L Milk & 3L water then
  
  Combining complete contain of A & B to C we get 6L milk & 6L water
  
  If half taken then from A - 2:1.5 & B - 1:1.5 So in C - 3:3
  
  Hence 1:1 is the Ratio.
• 12 years agoHelpfull: Yes(2) No(11)
• Milk in 1 litre mixture of A = 4/7 litre.
  Milk in 1 litre mixture of B = 2/5 litre.
  Milk in 1 litre mixture of C = 1/2 litre.
  By rule of alligation we have required ratio X:Y
  
  X : Y
  
  4/7 2/5
  
  
  
  /
  
  (Mean ratio)
  (1/2)
  
  /
  
  (1/2 – 2/5) : (4/7 – 1/2)
  
  1/10 1/1 4
  
  
  
  So Required ratio = X : Y = 1/10 : 1/14 = 7:5
  
• 8 years agoHelpfull: Yes(1) No(0)
• 1;1 is ans
• 9 years agoHelpfull: Yes(0) No(2)