4 men can repair a road in 7 hours. how many men are required to repair the road in 2 hours

• M * T / W = Constant
  where, M= Men (no. of men)
  T= Time taken
  W= Work load
  So, here we apply
  M1 * T1/ W1 = M2 * T2 / W2
  Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?
  Note that here, W1 = W2 = 1 road, ie. equal work load.
  Clearly, substituting in the above equation we get, M2 = 14 men.
• 9 years agoHelpfull: Yes(10) No(0)
• 1hr 1men work=1/4*7=1/28
  2hr work=2/28=1/14
  14 men can complete in 2hrs
• 9 years agoHelpfull: Yes(6) No(0)
• Ans 14 men are required.
• 9 years agoHelpfull: Yes(2) No(0)
• M1*D1*W2=M2*D2*W1
  HERE W1=W2
  4*7*1=M2*2*1
  M2=14
• 8 years agoHelpfull: Yes(2) No(0)
• 14 men are required to do the work in 2 hours.
• 9 years agoHelpfull: Yes(1) No(0)
• M x T / W = Constant
  where, M= Men (no. of men)
  T= Time taken
  W= Work load
  So, here we apply
  M1 x T1/ W1 = M2 x T2 / W2
  Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?
  Note that here, W1 = W2 = 1 road, ie. equal work load.
  Clearly, substituting in the above equation we get, M2 = 14 men.
• 5 years agoHelpfull: Yes(1) No(0)
• 4men required to repare7hrs
  then one man required to repair = (4*7)
  same wrk in 2 hrs
  4*7/2= 14
  
• 9 years agoHelpfull: Yes(0) No(0)
• If more men work it will take less days so they are inversely proportional..
  4/x=2/7=>x=14
• 9 years agoHelpfull: Yes(0) No(0)
• we known that
  4*7=y*2
  y=14
• 7 years agoHelpfull: Yes(0) No(0)