The ages of two friends is in the ratio 6:5. The sum of their ages is 66.After how many years will the ages be in the ratio 8:7?

• 6x+5x=66,x=6
  then multiply x with first ratio i.e 6(6)/5(6)=36/30
  multiply x with second ratio 8(6)/7(6)=48/42
  difference between the above ratios numerator is 48-36=12 years
• 11 years agoHelpfull: Yes(8) No(0)
• Ans=12 years
  If the ages are x and y, then Given x/y=6/5 & x+y=66
  Solving these two eqn. we get x=30, y=36
  If the ratio becomes 8/7, after say z years,then (x+z)/(y+z)=8/7
  Substituting values of x & y, (36+z)/(30+z)=8/7, 252+7z=240+8z ->z=12
• 11 years agoHelpfull: Yes(6) No(2)
• 6x+5x=66 so, x=11
  Now [6(11)+y]/[5(11)+y]=8/7
  On solving y=22 years
• 11 years agoHelpfull: Yes(2) No(16)
• 6x+5x=66
  hence x=6
  now as per the given condition: [6(6)+y/5(6)+y]=[8/7]
  on solving the above equation ans will be 12 yrs.
• 11 years agoHelpfull: Yes(1) No(0)
• Sorry guys, calculation mistake it was.
• 11 years agoHelpfull: Yes(1) No(0)