in base 7,a number is written only using the digits 0,1,....6.the number 135 in base 7 is 1x7^2+3x7+5=75 in base 10.what is the sum of the same of the base 7 numbers 1234 and 6543 in base 7?

• 11110
  
  1234
  6543
  -------
  11110 which is 7^4+7^3+7^2+7= 2401+343 +49+7= 2800
• 12 years agoHelpfull: Yes(31) No(3)
• 1234=1*7^3+2*7^2+3*7^1+4 =343+98+21+4= 466
  
  6543=6*7^3+5*7^2+4*7^1+3 =2058+245+28+3= 2334
  
  466+2334=2800
  
  11110=7^4+7^3+7^2+7^1+0*7^0=2401+343+49+7+0= 2800
  Answer: 11110
• 12 years agoHelpfull: Yes(18) No(1)
• @ Sanket,
  Pls check
  
  1234 in base 7=1*7^3+2*7^2+3*7^1+4 = 343+98+21+4 = 466
• 12 years agoHelpfull: Yes(2) No(7)
• 1234=1*7^3+2*7^2+3*7^1+4 = 343+89+21+4 = 462
  
  6543=6*7^3+5*7^2+4*7^1+3 = 2058+245+28+3 = 2334
  
  462+2334=2796
• 12 years agoHelpfull: Yes(1) No(13)
• @sanket
  6543=(6x7^3)+(5x7^2)+(4x7)+3=2934
  
  2934+466=3500
• 12 years agoHelpfull: Yes(0) No(3)