SSC
Government Jobs Exams
Numerical Ability
Arithmetic
If p=99, then the value of p(p^2+3p+3) is
a)999999 b)10000001 c)9999999 d)1000001
Read Solution (Total 2)
-
- p(p^2+3p+3)
= p^3+3p^2+3p
= p^3+3p^2+3p +1 -1
=(p+1)^3 -1
=(99+1)^3 -1
= 1000000 - 1
= 999999 - 9 years agoHelpfull: Yes(3) No(0)
- ans is a 999999
- 9 years agoHelpfull: Yes(1) No(1)
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